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AleksAgata [21]
3 years ago
15

What is the product 18 x 8​

Mathematics
2 answers:
Mariana [72]3 years ago
5 0

Answer:144

Step-by-step explanation:

Veseljchak [2.6K]3 years ago
3 0

Answer:

144

Step-by-step explanation:

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Sam is 4 feet and 5 inches tall. if sam grows 11 more inches, what will be his new height?
jok3333 [9.3K]
Sam will be 5 foot 4 inches
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What is 74 times 98 add 65?
vitfil [10]

Answer:

7317

Step-by-step explanation:

74x98+65=7317

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The middle school basketball team is selling t-shirts for $12.50 each to raise money for new uniforms. They have already sold 40
Rama09 [41]

Step-by-step explanation:

given:

$12.50- the price of the tshirts

40- the tshirts they have sold

$850- the raise they need

solve:

$12.50 × 40 = $500 (the price of tshirts and tshirts they have sold)

$850 - $500 = $350 (the raise they need and the money they have so far from the 40 tshirts they have sold)

$350 ÷ $12.50 = 28 (the money they lack and the price of a tshirt)

answer:

thus, they need to sell 28 more tshirts to have the raise of at least $850

hope this helps, good luck! :)

8 0
3 years ago
Read 2 more answers
If a boat uses 15 gallons of gas to travel 70 miles, how many miles can the boat travel on 60 gallons of gas?
astra-53 [7]

Answer:

280 miles

Step-by-step explanation:

First you multiply 15 x 4= 60 gallons. You then multiply 4 x 70=280 miles

Hope this helps!

7 0
3 years ago
An article in Knee Surgery, Sports Traumatology, Arthroscopy, "Arthroscopic meniscal repair with an absorbable screw: results an
igomit [66]

Answer:

Mean = 1.57

Variance=0.31

Step-by-step explanation:

To calculate the mean and the variance of the number of successful surgeries (X), we first have to enumerate the possible outcomes:

1) Both surgeries are successful (X=2).

P(e_1)=0.90*0.67=0.603

2) Left knee unsuccessful and right knee successful (X=1).

P(e_2)=(1-0.9)*0.67=0.1*0.67=0.067

3) Right knee unsuccessful and left knee successful (X=1).

P(e_3)=0.90*(1-0.67)=0.9*0.33=0.297

4) Both surgeries are unsuccessful (X=0).

P(e_4)=(1-0.90)*(1-0.67)=0.1*0.33=0.033

Then, the mean can be calculated as the expected value:

M=\sum p_iX_i=0.603*2+0.067*1+0.297*1+0.033*0\\\\M=1.206+0.067+0.297+0\\\\M=1.57

The variance can be calculated as:

V=\sum p_i(X_i-\bar{X})^2\\\\V=0.603(2-1.57)^2+(0.067+0.297)*(1-1.57)^2+0.033*(0-1.57)^2\\\\V=0.603*0.1849+0.364*0.3249+0.033*2.4649\\\\V=0.1115+0.1183+0.0813\\\\V=0.3111

3 0
3 years ago
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