Question

An air-track glider attached to a spring oscillates between the 15.0 cm mark and the 68.0 cm mark on the track. The glider completes 7.00 oscillations in 31.0 s . What is the period of the oscillations?

Answer 1

Answer:

4.42 s

Explanation:

The frequency of the oscillation is given by the ratio between the number of complete oscillations and the time taken:

$f=\frac{N}{t}$

where for this glider, we have

N = 7.00

t = 31.0 s

Substituting, we find

$f=\frac{7.00}{31.0 s}=0.226 Hz$

Now we now that the period of oscillation is the reciprocal of the frequency:

$T=\frac{1}{f}$

So, substituting f = 0.226 Hz, we find:

$T=\frac{1}{0.226 Hz}=4.42 s$