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storchak [24]
3 years ago
7

An air-track glider attached to a spring oscillates between the 15.0 cm mark and the 68.0 cm mark on the track. The glider compl

etes 7.00 oscillations in 31.0 s . What is the period of the oscillations?
Physics
1 answer:
ipn [44]3 years ago
6 0

Answer:

4.42 s

Explanation:

The frequency of the oscillation is given by the ratio between the number of complete oscillations and the time taken:

f=\frac{N}{t}

where for this glider, we have

N = 7.00

t = 31.0 s

Substituting, we find

f=\frac{7.00}{31.0 s}=0.226 Hz

Now we now that the period of oscillation is the reciprocal of the frequency:

T=\frac{1}{f}

So, substituting f = 0.226 Hz, we find:

T=\frac{1}{0.226 Hz}=4.42 s

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valina [46]

Zero.

Acceleration is defined as the change in velocity over time.

Since in your case there is no change, there is no acceleration, so it is zero:

Or in formula: <span>a=<span><span>Δv</span>t</span></span>

Where a=acceleration, <span>Δv</span>=change in velocity and t=time

6 0
3 years ago
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A wrench is accidentally dropped from the top of a mast on a sailboat. Will the wrench hit at the same place on the deck whether
alekssr [168]

Answer:

Yes, because the wrench is moving at the same speed as the sailboat.

The main difference is that a person on the ground would see the wrench moving diagonally, while a person on the boat would see the wrench falling straight down,

This difference in paths lead to the relativistic change in lengths.

8 0
4 years ago
As you travel from Detroit in a certain direction, the outside temperature, T (in degrees), depends on your distance, d (in mile
Ber [7]

Answer:

a)\Delta T= 100^{\circ}C

b)\bigtriangledown T=1^{\circ}C.mile^{-1}

c)\bigtriangledown T_4=1^{\circ}C.mile^{-1}

d)\bigtriangledown T_4=1^{\circ}C.mile^{-1}

Explanation:

Given is the data of variation of temperature with respect to the distance traveled:

Temperature T as a function of distance d:

T=(d+30) ^{\circ}C...................................(1)

(a)

Total change in temperature from the start till the end of the journey:

\Delta T= T_f-T_i..............................(2)

where:

T_f= final temperature

T_i= initial temperature

∵In the start of the journey d = 0 miles & at the end of the journey d = 100 miles.

So, correspondingly we have the eq. (2) & (1) as:

\Delta T= (100+30)-(0+30)

\Delta T= 100^{\circ}C

(b)

Now, the average rate of change of the temperature, with respect to distance, from the beginning of the trip to the end of the trip be calculated as:

\bigtriangledown T=\frac{\Delta T}{\Delta d}......................(3)

where:

\Delta d= change in distance

\bigtriangledown T=change in temperature with respect to distance

putting the respective values in eq. (3)

\bigtriangledown T=\frac{100}{100}

\bigtriangledown T=1^{\circ}C.mile^{-1}

(c)

comparing the given function of the temperature with the general equation of  a straight line:

y=m.x+c

We find that we have the slope of the equation as 1 throughout the journey and therefore the rate of change in temperature with respect to distance remains constant.

\bigtriangledown T_4=1^{\circ}C.mile^{-1}

(d)

comparing the given function of the temperature with the general equation of  a straight line:

y=m.x+c

We find that we have the slope of the equation as 1 throughout the journey and therefore the rate of change in temperature with respect to distance remains constant.

\bigtriangledown T_4=1^{\circ}C.mile^{-1}

4 0
4 years ago
What radiant energy is sensed by human skin as warmth
almond37 [142]
Infrared radiation <span>is sensed by human skin as warmth.</span>
4 0
3 years ago
A block floats partially submerged in a container of liquid. When the entire container is accelerated upward, which of the follo
Nookie1986 [14]

Answer:C

Explanation:

Partially submerged block along with vessel is accelerated upwards .

Initially the block weight is supported by buoyant force such that it is in equilibrium.

when the system start accelerating upwards then the effective gravity will be

g+a where a is the acceleration of the system.

so only net gravity is increased so block will not ascend or descend.

Mathematically

F_b=weight

\rho _L\cdot V\cdot (g+a)=m(g+a)

where \rho _L=density of liquid

V=volume of object inside the water

                         

7 0
3 years ago
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