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3 years ago

How far would you travel in 10 seconds if you are moving at 15 m/s?

Physics

2 answers:

Vikki [24]3 years ago

6 0

Answer:

150 m

Explanation:

distance = speed x time

so 10 x 15 = 150

DIA [1.3K]3 years ago

6 0

Answer:

Explanation:

distance = velocity ( time)

= 15 m/s ( 10 secs)

= 150 m

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Space pilot Mavis zips past Stanley at a constant speed relative to him of 0.800c. Mavis and Stanley start timers at zero when t

yawa3891 [41]

Answer:

a) $x=2*10^{9} m$ and $t=8.35 s$

b) t = γt', so it is 8.35 s.

Explanation:

a) The equation of Lorentz transformations is given by:

$x=\gamma(x'+ut')$

x' and t' are the position and time in the moving system of reference, and u is the speed of the space ship. x is related to the observer reference.

x' = 0
t' = 5.00 s
u =0.800 c, c is the speed of light 3*10⁸ m/s

$\gamma=\frac{1}{\sqrt{1-(u/c)^{2}}}$

$\gamma=\frac{1}{\sqrt{1-(0.800c/c)^{2}}}$

$\gamma=\frac{1}{\sqrt{1-(0.800)^{2}}}$

$\gamma=1.67$

$x=1.67(0+0.800c*5.00)$

$x=2*10^{9} m$

Now, to find t we apply the same analysis:

$t=\gamma(t'+\frac{ux'}{c^{2}})$

but as x'=0 we just have:

$t=\gamma(t')$

$t=1.67*5.00=8.35 s$

b) Here, Mavis reads 5 s on her watch and Stanley measured the events at a time affected by the Lorentz factor, in other words t = γt', if we see it is the same a) part. So the time interval will be equal to 8.35 s.

I hope it helps you!

5 0

3 years ago

Read 2 more answers

What is the name for a star and planets held together by gravity? A. solar system B. galaxy C. black hole D. supernova

DaniilM [7]

These answers aren´t valid .

The correct answer will be:

Planetary system.

5 0

3 years ago

Your outlets at home are rated at 120 V, i.e. the two prongs have on average a potential difference of 120V. If you transfer 2.7

hodyreva [135]

Answer:

E =230.4 MJ

Explanation:

As 1 mole of electron = 6X 10^23 particles.

charge of an electron is 1.6 X 10 ^-19 C

Finding Charge:

(6X10^23 ) (2.7)(1.6X10^-19 C)

i.e. 192 K C

now to find the energy released from electrons

V=E/q

E=V X q

i.e E = 120 V X 192 K C

E =230.4 MJ

4 0

3 years ago

Problem 6.056 Air enters a compressor operating at steady state at 15 lbf/in.2, 80°F and exits at 275°F. Stray heat transfer and

vova2212 [387]

To solve this process it is necessary to consider the concepts related to the relations between pressure and temperature in an adiabatic process.

By definition the relationship between pressure and temperature is given by

$(\frac{P_2}{P_1})=(\frac{T_2}{T_1})^{(\frac{\gamma}{\gamma-1})}$

Here

P = Pressure

T = Temperature

$\gamma =$ The ratio of specific heats. For air normally is 1.4.

Our values are given as,

$P_1 = 15lb/in^2\\T_1= 80\°F = 299.817K\\T_2 =400\°F = 408.15K$

Therefore replacing we have,

$(\frac{P_2}{P_1})=(\frac{T_2}{T_1})^{(\frac{\gamma}{\gamma-1})}$

$(\frac{P_2}{15})=(\frac{408.15}{299.817})^{(\frac{1.4}{1.4-1})}$

Solving for $P_2,$

$P_2 = 15*(\frac{408.15}{299.817})^{(\frac{1.4}{1.4-1})}$

$P_2 = 44.15Lbf/in^2$

Therefore the maximum theoretical pressure at the exit is $44.15Lbf/in^2$

5 0

3 years ago

When four quadruplets cry simultaneously, how many decibels greater is the sound intensity level than when a single one cries?

Ket [755]

Answer:

Explanation:

Assume that a single baby cries at X db

4 babies crying would be X + 10log₁₀(4) = X + 6 db

8 0

2 years ago

How far would you travel in 10 seconds if you are moving at 15 m/s?​

How far would you travel in 10 seconds if you are moving at 15 m/s?