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3 years ago

Key concepts (Example | scientific method

Physics

2 answers:

motikmotik3 years ago

8 0

Answer: planning an investigation

Explanation:

nekit [7.7K]3 years ago

3 0

Vocabulary should be, I think:
I. Hypothesis
II. Evidence, data
III. Experiment

What is your question exactly?

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The rectangular boat shown below has base dimensions 10.0 cm × 8.0 cm. Each cube has a mass of 40 g, and the liquid in the tank

spin [16.1K]

Answer:

A that the answer I think I'm not tryna do u bad thi

Explanation:

but try it

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4 years ago

(35 points!!) A block and tackle is used to lift a load weighing 600 lb. The operator lifts the load distance of 1.25 ft by pull

Drupady [299]

Answer:

A. Input work = 800 ft.lb

B. Output work = 750 ft.lb

C. Efficiency of block and tackle = 93.75 %

Explanation:

Given:

Weight of the load, $W=600$ lb.

Distance moved by the load, $D_{load}=1.25$ ft.

Force applied on the rope, $F = 200$ lb

Distance moved by the force on the rope, $D{in}=4$ ft.

Work done by a force causing a displacement in the direction of force is given as:

$\textrm{Work}=\textrm{Force}\times \textrm{Displacement}$

Here, Input Work is given by the input force and the displacement caused by the input force. So,

$W_{in}=F\times D_{in}\\W_{in}=200\times 4=800\textrm{ ft.lb}$

Therefore, the input work is 800 lb.ft

Output Work is given by the output force and the displacement caused by the output force. So,

$W_{out}=F_{load}\times D_{load}\\W_{out}=600\times 1.25=750\textrm{ ft.lb}$

Therefore, the output work is 750 ft.lb

Efficiency is given as the ratio of Output Work to Input Work expressed as percentage. So,

Efficiency = $\frac{W_{out}}{W_{in}}\times 100=\frac{750}{800}\times 100=93.75\%$

Therefore, efficiency of block and tackle is 93.75 %.

6 0

3 years ago

Read 2 more answers

A ball whose mass is 0.4 kg hits the floor with a speed of 8 m/s and rebounds upward with a speed of 6 m/s. Collapse question pa

Colt1911 [192]

Answer:

The the average magnitude of the force exerted on the ball by the floor $11.2 \times 10^{3}$ N

Explanation:

Given:

Mass of ball $m = 0.4$ kg

Initial speed $v_{i} = -8 \frac{m}{s}$

Rebound speed $v_{f} = 6 \frac{m}{s}$

Contact time interval $\Delta t = 0.5 \times 10^{-3}$ sec

For finding the average magnitude of the force on the ball by the floor is given by,

$F_{avg} = \frac{\Delta P}{\Delta t}$

Here $\Delta P = m (v_{f}- v_{i} )$

$F_{avg} = \frac{m (v_{f} -v_{i} )}{\Delta t}$

$F_{avg} = \frac{0.4 \times (6 -( -8 ) )}{0.5 \times 10^{-3} }$

$F_{avg} = 11.2 \times 10^{3}$ N

Therefore, the the average magnitude of the force exerted on the ball by the floor $11.2 \times 10^{3}$ N

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3 years ago

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The dimension of a room has 5.31m by 7.6m. Find the limits of accuracy for the area of the room

balu736 [363]

Explanation:

Se supone que si es 5.31 x 7.6 los límites son 38.98 ahora si fuera en suma mueves los puntos dos veces a la izquierda la sumatoria seria la siguiente .00531 + .0076 la respuesta seria

.00607

4 0

3 years ago

What is "the cloud"?

Sedaia [141]

Answer:

Cloud is a condensed from of atmospheric moisture consisting of small water droplets.

Clouds cause rainfall and snow fall.

Different types of clouds are found in the atmosphere. Some main types of them are cirrus, cumulus, nimbus, and stratus. Most clouds are generated by the cooling of air as it rises.

6 0

3 years ago

Read 2 more answers