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viva [34]
2 years ago
8

An athletes heart beats 62 times per minute. What is the frequency of her heart beat?

Physics
1 answer:
PilotLPTM [1.2K]2 years ago
8 0

Answer:

22

Explanation:

bc it just is

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A room has a heater on one side and
Serjik [45]

Answer:

the warm air would be up and cool would be down

Explanation:

warm air is less dense and cool air is more dense

5 0
2 years ago
An observation of the red shift of galaxies suggestst that the universe is
Rufina [12.5K]
A) Expanding. We know this because it has a similar effect with sound. When a car goes by the pitch gets deeper and deeper. It's because you're receiving less waves. Same thing for light but instead of a pitch it's light, and the farther spread the waves - the redder, the closer and more contracted - the bluer
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2 years ago
Reasons<br> why using mirrors to generate electricity is not a common practice.  
olganol [36]
A big part of the reason that mirrors are seldom if ever used to generate
electricity is the simple fact that there is no way to generate electricity using
mirrors.  They are as useless for the purpose as smoke is, although there are
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7 0
3 years ago
Read 2 more answers
In physics class, Carrie learns that a force, F, is equal to the mass of an object, m, times its acceleration, a. She writes the
Phantasy [73]

Answer:

2.2 m/s^2

Explanation:

Acceleration = Force / Mass

= 7.92 / 3.6 = 2.2m/s^2

Hope this help you :3

5 0
2 years ago
Read 2 more answers
To calibrate the calorimeter electrically, a constant voltage of 3.6 V is applied and a current of 2.6 A flows for a period of 3
iren [92.7K]

Answer:

372.3 J/^{\circ}C

Explanation:

First of all, we need to calculate the total energy supplied to the calorimeter.

We know that:

V = 3.6 V is the voltage applied

I = 2.6 A is the current

So, the power delivered is

P=VI=(3.6)(2.6)=9.36 W

Then, this power is delivered for a time of

t = 350 s

Therefore, the energy supplied is

E=Pt=(9.36)(350)=3276 J

Finally, the change in temperature of an object is related to the energy supplied by

E=C\Delta T

where in this problem:

E = 3276 J is the energy supplied

C is the heat capacity of the object

\Delta T =29.1^{\circ}-20.3^{\circ}=8.8^{\circ}C is the change in temperature

Solving for C, we find:

C=\frac{E}{\Delta T}=\frac{3276}{8.8}=372.3 J/^{\circ}C

5 0
2 years ago
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