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MA_775_DIABLO [31]
3 years ago
5

Examine the scenario.

Physics
1 answer:
zhannawk [14.2K]3 years ago
6 0

The electrons in the positive object are attracted to the negatively charged object. Some of the electrons move from the positive object to the negative object.

an example of this is lightning because the positive electrons on/in the earth are attracted to the negative electrons in the clouds and sky so the positive move to the negative charge.

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Estimate the acceleration you subject yourself to if you walk into a brick wall at normal walking speed. (Make a reasonable esti
xenn [34]

Answer:

From certain assumptions that the walking speed is 2 m/s, and the stop time is 0.1 s the acceleration would be -20 m/s

Explanation:

Using the average acceleration formula:

a=\frac{\Delta v}{\Delta t} where \Delta v and \Delta t are the changes in the speed and time respectively.

We have by assuming that the walking speed is 2 m/s and the stop time is 0.1s which is equal to the change in time during the stopping.

\Delta v=v_f-v_i=0-2 m/s=-2 m/s, where v_i,v_f are the initial speed and final speed respectively, and \Delta t=0.1 s

Plugging the previous in the average acceleration formula we get

a=\frac{-2}{0.1}=-20\, m/s where the minus sign indicates an acceleration in the opposite direction of the motion (or in other word opposite to the speed's direction).

4 0
3 years ago
What is the magnitude of the net torque on the pulley about the axle?
jeyben [28]

Answer: Torque= tangential force × radius of the pulley

Explanation:

Pulley is a simple machine which helps us to lift loads by applying the force in a convenient direction. It consists of a grooved wheel which is free to rotate about an axle passing through the center of the pulley.

For a pulley, the torque T= tangential force × radius of the pulley

Pulleys can be used in combination also to achieve a desired output.

6 0
3 years ago
A 0.25-m string, vibrating in its sixth harmonic, excites a 0.96-m pipe that is open at both ends into its second overtone reson
Andrews [41]

Answer:

option D

Explanation:

given,

length of the pipe, L = 0.96 m

Speed of sound,v = 345 m/s

Resonating frequency when both the end is open

f = \dfrac{nv}{2L}

n is the Harmonic number

2nd overtone = 3rd harmonic

so, here n = 3

now,

f = \dfrac{3\times 345}{2\times 0.96}

f = 540 Hz

The common resonant frequency of the string and the pipe is closest to 540 Hz.

the correct answer is option D

7 0
3 years ago
Please I need help........
LenKa [72]

Answer:

7.46 J/kg/K

Explanation:

The heat absorbed or lost is:

q = mCΔT

where m is the mass, C is the heat capacity, and ΔT is the change in temperature.

Given q = 15.0 J, m = 0.201 kg, and ΔT = 10.0 °C:

15.0 J = (0.201 kg) C (10.0 °C)

C = 7.46 J/kg/°C

Which is the same as 7.46 J/kg/K.

7 0
2 years ago
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3 years ago
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