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MA_775_DIABLO [31]

3 years ago

5

Examine the scenario.

1 answer:

zhannawk [14.2K]3 years ago

6 0

The electrons in the positive object are attracted to the negatively charged object. Some of the electrons move from the positive object to the negative object.

an example of this is lightning because the positive electrons on/in the earth are attracted to the negative electrons in the clouds and sky so the positive move to the negative charge.

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The spans of time that make up the Earth's geologic timescale are generally defined by the different types of

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<span>division of Earth's history into time units based largely on the types of life-forms that lived only during certain periods.</span>

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3 years ago

Jupiter has the strongest gravity of any planet in our solar system. Which quantity will be a maximum there?

Mamont248 [21]

weight will be maximum there

3 0

3 years ago

Determine the angle of an incline that would yield a constant velocity, given the coefficient of kinetic friction is 0.10.

azamat

Answer:

$\theta=5.71^{o}$

Explanation:

In order to solve this problem, we mus start by drawing a free body diagram of the given situation (See attached picture).

From the free body diagram we can now do a sum of forces in the x and y direction. Let's start with the y-direction:

$\sum F_{y}=0$

$-W_{y}+N=0$

$N=W_{y}$

so:

$N=mgcos(\theta)$

now we can go ahead and do a sum of forces in the x-direction:

$\sum F_{x}=0$

the sum of forces in x is 0 because it's moving at a constant speed.

$-f+W_{x}=0$

$-\mu_{k}N+mg sen(\theta)=0$

$-\mu_{k}mg cos(\theta)+mg sen(\theta)=0$

so now we solve for theta. We can start by factoring mg so we get:

$mg(-\mu_{k} cos(\theta)+sen(\theta))=0$

we can divide both sides into mg so we get:

$-\mu_{k} cos(\theta)+sen(\theta)=0$

this tells us that the problem is independent of the mass of the object.

$\mu_{k} cos(\theta)=sen(\theta)$

we now divide both sides of the equation into $cos(\theta)$ so we get:

$\mu_{k}=\frac{sen(\theta)}{cos(\theta)}$

$\mu_{k}=tan(\theta)$

so we now take the inverse function of tan to get:

$\theta=tan^{-1}(\mu_{k})$

so now we can find our angle:

$\theta=tan^{-1}(0.10)$

so

$\theta=5.71^{o}$

8 0

3 years ago

1. After a rabbit population reaches the carrying capacity of its habitat, what will most likely happen to

kifflom [539]

C) alternately increase and decrease

6 0

3 years ago

A cricket starts at the 5 meter mark on a ruler. It jumps to the 10 meter mark. Then, it jumps back to the 6 meter mark. Calcula

belka [17]

We have that the cricket’s displacement is

$D_t=9meters$

From the Question we are told that

Start position 5 meter mark

It jumps to the 10 meter mark.

it jumps back to the 6 meter mark.

Generally the equation for cricket’s displacement. is mathematically given as

$D_t=Initial +final(displacement)\\\\D_t=(10-5)+(10-6)$

$D_t=9meters$

For more information on this visit

brainly.com/question/24273210?referrer=searchResults

4 0

3 years ago