Solids have molecules that move slowly and are close together and are very attracted to eachother.
Liquids have molecules that move freely and are slightly attracted to eachother.
Gases have molecules that move, but aren't attracted to eachother.
Let d = distance that the fugitive travels to get on the train.
Let t = the time to travel the distance d.
The fugitive starts from rest accelerates at a = 3.8 m/s².
Therefore
(1/2)*(3.8 m/s²)*(t s)² = (d m)
1.9 t² = d (1)
The train travels at constant speed 5.0 m/s.
Therefore
(5.0 m/s)*(t s) = d
5t = d (2)
If the fugitive successfully boards the train, then equate (1) and (2).
1.9t² = 5t
t = 0 or t = 2.6316 s
Ignore t = 0, so t = 2.6316 s.
The speed of the fugitive after 2.6316 s, is
v = (3.8 m/s²)*(2.6316 s) = 10 s
This speed exceeds the maximum speed of the fugitive, therefore the fugitive fails to get on the train.
Answer: The fugitive fails to get on the train.
When the launch velocity is a bit less than the escape velocity, the satellite with time will find itself back to earth and when the speed is far beyond the escape velocity, the satellite with time, be lost in space.
The velocity of escape from the less massive Moon is about 2.4 km per second at its surface. ... A planet (or satellite) cannot long retain an atmosphere if the planet's escape velocity is low enough to be near the average velocity of the gas molecules making up the atmosphere.
