Preload ensures that enough pressure is placed on the bearing, so as to keep the shaft from moving around while preventing the bearing from running hot.
<h3>What is preload?</h3>
Preload can be defined as the load (amount of force) that is generated from an axial interference within a bearing, which causes an elastic deformation between the rolling elements and raceway.
In Engineering, preload is a technique which ensures that enough pressure is placed on the bearing, so as to keep the shaft from moving around while preventing the bearing from running hot and failing.
Read more on preload here: brainly.com/question/16342676
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Answer: The function of an electric switch is to regulate the current between the load and source of the power. The power source is the electrons that push through the circuits. ... The load receives the current and returns it via the positive terminal to the power source. The electrical switch is inserted
Explanation: hope this helps :)
Answer:
W=2 MW
Explanation:
Given that
COP= 2.5
Heat extracted from 85°C
Qa= 5 MW
Lets heat supplied at 150°C = Qr
The power input to heat pump = W
From first law of thermodynamics
Qr= Qa+ W
We know that COP of heat pump given as
![COP=\dfrac{Qr}{W}](https://tex.z-dn.net/?f=COP%3D%5Cdfrac%7BQr%7D%7BW%7D)
![2.5=\dfrac{5}{W}](https://tex.z-dn.net/?f=2.5%3D%5Cdfrac%7B5%7D%7BW%7D)
![2.5=\dfrac{5}{W}](https://tex.z-dn.net/?f=2.5%3D%5Cdfrac%7B5%7D%7BW%7D)
W=2 MW
For Carnot heat pump
![COP=\dfrac{T_2}{T_2-T_1}](https://tex.z-dn.net/?f=COP%3D%5Cdfrac%7BT_2%7D%7BT_2-T_1%7D)
![2.5=\dfrac{T_2}{T_2-(273+85)}](https://tex.z-dn.net/?f=2.5%3D%5Cdfrac%7BT_2%7D%7BT_2-%28273%2B85%29%7D)
2.5 T₂ - 895= T₂
T₂=596.66 K
T₂=323.6 °C
Don't repeat yourself (DRY, or sometimes do not repeat yourself) is a principle of software development aimed at reducing repetition of software patterns,[1] replacing it with abstractions or using data normalization to avoid redundancy.