Answer:
ACCIDENT PREVENTION RECOMMENDATIONS
Fatal Fact made us to understand some of the prevention techniques as stated below.
1. Use approved ground fault circuit interrupters or an assured equipment grounding conductor program to protect employees on construction sites.
2. Use equipment that provides a permanent and continuous path from circuits, equipment, structures, conduit or enclosures to ground.
3. Inspect electrical tools and equipment daily and remove damaged or defective equipment from use until it is repaired.
Explanation:
In order to gain a better understanding of the answer above let explain some terms
Ground Fault Circuit Interrupters :
A ground fault circuit interrupter (GFCI), or Residual Current Device (RCD) is a type of circuit breaker which shuts off electric power when it senses an imbalance between the outgoing and incoming current. The main purpose is to protect people from an electric shock caused when some of the current travels through a person's body due to an electrical fault such as a short circuit, insulation failure, or equipment malfunction.
So the first statement is implying that in order to prevent this accident that this device (GFCI) should have been used in that construction site, or as an alternative before the construction commenced the company should have drafted a lay down conductor program(i.e. a step by step conductor program) that assured equipment grounding in order to protect employees on construction sites
Answer:
use Bluetooth if you have an unwired controller, but If its wired just hook it up.
Answer:
1) the final temperature is T2 = 876.76°C
2) the final volume is V2 = 24.14 cm³
Explanation:
We can model the gas behaviour as an ideal gas, then
P*V=n*R*T
since the gas is rapidly compressed and the thermal conductivity of a gas is low a we can assume that there is an insignificant heat transfer in that time, therefore for adiabatic conditions:
P*V^k = constant = C, k= adiabatic coefficient for air = 1.4
then the work will be
W = ∫ P dV = ∫ C*V^(-k) dV = C*[((V2^(-k+1)-V1^(-k+1)]/( -k +1) = (P2*V2 - P1*V1)/(1-k)= nR(T2-T1)/(1-k) = (P1*V1/T1)*(T2-T1)/(1-k)
W = (P1*V1/T1)*(T2-T1)/(1-k)
T2 = (1-k)W* T1/(P1*V1) +T1
replacing values (W=-450 J since it is the work done by the gas to the piston)
T2 = (1-1.4)*(-450J) *308K/(101325 Pa*650*10^-6 m³) + 308 K= 1149.76 K = 876.76°C
the final volume is
TV^(k-1)= constant
therefore
T2/T1= (V2/V1)^(1-k)
V2 = V1* (T2/T1)^(1/(1-k)) = 650 cm³ * (1149.76K/308K)^(1/(1-1.4)) = 24.14 cm³
Answer:
yes i have 2 huge bins of it
Explanation:
