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3 years ago

8

What would be the most likely scale factor to use for an n-gauge model train setup? (An n-gauge layout uses locomotives that are

typically about five centimeters long, on a train platform that may be one meter by one meter.)
A. 1:100
B. 1:500
C. 100:1
D. 500:1

1 answer:

slega [8]3 years ago

8 0

A or b for sure brother

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simply supported beam is subjected to a linearly varying distributed load ( ) 0 q x x L 5 q with maximum intensity 0 q at B. The

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Answer:

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Given

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We can see the pic shown in order to understand the question.

We apply

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Then, we apply

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Then, we can get the maximum bending moment as follows

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then we get

$M(\frac{4}{\sqrt{3} })=-\frac{q_{0}}{6*4} (\frac{4}{\sqrt{3} })^{3}+\frac{q_{0} *4}{6}(\frac{4}{\sqrt{3} })\\ M(\frac{4}{\sqrt{3} })=-\frac{8}{9\sqrt{3} } q_{0} +\frac{8}{3\sqrt{3} } q_{0}=\frac{16}{9\sqrt{3} } q_{0}m^{2}$

We get the inertia as follows

$I=\frac{w*h^{3} }{12} \\ I=\frac{0.2m*(0.3m)^{3} }{12}=4.5*10^{-4}m^{4}$

We use the formula

σ = M*y/I

⇒ M = σ*I/y

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If M = Mmax, we have

$(\frac{16}{9\sqrt{3} }m^{2} ) q_{0}\leq \frac{120*10^{6}Pa*4.5*10^{-4}m^{4} }{0.15m}\\ q_{0}\leq 350,740.2885\frac{N}{m}$

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Answer:

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