Answer:
The ground-fault circuit interrupter, or GFCI, is a fast-acting circuit breaker designed to shut off electric power in the event of a ground-fault within as little as 1/40 of a second.
Explanation:
Answer:
The required heat flux = 12682.268 W/m²
Explanation:
From the given information:
The initial = 25°C
The final = 75°C
The volume of the fluid = 0.2 m/s
The diameter of the steel tube = 12.7 mm = 0.0127 m
The fluid properties for density
= 1000 kg/m³
The mass flow rate of the fluid can be calculated as:




To estimate the amount of the heat by using the expression:

q = 0.0253 × 4000(75-25)
q = 101.2 (50)
q = 5060 W
Finally, the required heat of the flux is determined by using the formula:



q" = 12682.268 W/m²
The required heat flux = 12682.268 W/m²
- The conversion of 47,000 Ohms to kilo-ohms is equal to 47 kilo-ohms.
- The conversion of 47,000 Ohms to mega-ohms is equal to 0.047 kilo-ohms.
<h3>What is
resistance?</h3>
Resistance can be defined as an opposition to the flow of current in an electric circuit. Also, the standard unit of measurement of the resistance of an electric component is Ohms, which can be converted to kilo-ohms or mega-ohms.
For Ohms to kilo-ohms, we have:
1 Ohms = 0.001 kilo-ohms
47,000 Ohms = X kilo-ohms
Cross-multiplying, we have:
X = 0.001 × 47000
X = 47 kilo-ohms.
For Ohms to mega-ohms, we have:
1,000,000 ohms = 1 mega-ohms
47,000 Ohms = X mega-ohms
Cross-multiplying, we have:
X1,000,000 = 47,000
X = 47,000/1,000,000
X = 0.047 kilo-ohms.
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Answer:
If analyzed by volume capacity, more trips are needed to fill the space, thus the required trips are 288
Explanation:
a) By volume.
The shrinkage factor is:

The volume at loose is:

If the Herrywampus has a capacity of 30 cubic yard:

b) By weight
The swell factor in terms of percent swell is equal to:


The weight of backfill is:

The Herrywampus has a capacity of 40 ton:

If analyzed by volume capacity, more trips are needed to fill the space, thus the required trips are 288
Answer:
hello your question is incomplete attached below is the missing part and also attached is the solution
answer: a) 0.4801
b) 5.398 kw
c) 2.14
d) 12.72
Explanation:
The quality of the refrigerant at the evaporator inlet
h4 = hf4 + x4(hfx4)
Refrigeration load
Ql = m(h1-h4)
COP of the refrigerator
Ql / m(h2-h1) - Qm
Theoretical maximum refrigeration load
( Ql )max = COPr.rev * [m(h2-h1) - Qin]