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meriva
3 years ago
10

Order the steps to describe how information is sent. A signal is produced. A signal is seen, heard, or used. Radio waves are mod

ulated and amplified. Radio waves are amplified and demodulated.
Physics
1 answer:
nordsb [41]3 years ago
6 0

Answer:

A signal is produced.

Radio waves are modulated and amplified.

Radio waves are amplified and demodulated.

A signal is seen, heard, or used.

Explanation:

Communication is the method of transmitting information between two or more participants. A radio communication network is a set of static and wireless radio equipment developed to facilitate an entity by enabling particular modes of communication such as one-to-many and one-to-one communication. Radio waves are being used to transmit information spatially from the sender to receiver, by modulating the radio signal in the transmitter. The above steps explains the loop of the radio communication system.

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Find the resultant of the following forces: 3.0N east, 4.0N west, and 5.0N in a direction north 60° west.
zzz [600]

Answer:

5.5 N at 50.8° north of west.

Explanation:

To find the resultant of these forces, we have to resolve each force along the x- and y-direction, then find the components of the resultant force, and then calculate the resultant force.

The three forces are:

F_1=3.0 N (east)

F_2=4.0 N (west)

F_3=5.0 N (at 60° north of west)

Taking east as positive x-direction and north as positive y-direction, the components of the forces along the 2 directions are:

F_{1x}=3.0 N\\F_{1y}=0

F_{2x}=-4.0 N\\F_{2y}=0

F_{3x}=-(5.0)(cos 60^{\circ})=-2.5 N\\F_{3y}=(5.0)(sin 60^{\circ})=4.3 N

Threfore, the components of the resultant force are:

F_x=F_{1x}+F_{2x}+F_{3x}=3.0+(-4.0)+(-2.5)=-3.5 N\\F_y=F_{1y}+F_{2y}+F_{3y}=0+0+4.3=4.3 N

Therefore, the magnitude of the resultant force is

F=\sqrt{F_x^2+F_y^2}=\sqrt{(-3.5)^2+(4.3)^2}=5.5 N

And the direction is:

\theta=tan^{-1}(\frac{F_y}{|F_x|})=tan^{-1}(\frac{4.3}{3.5})=50.8^{\circ}

And since the x-component is negative, it means that this angle is measured as north of west.

7 0
3 years ago
Kawas 200 osebanywhes he remembered he had to return some books they​
tia_tia [17]
I think you need to add more.. but I may know where you are leading

Was he 200 m away and made the trip in 200 seconds?

If yes...
2 m/s was his speed and 0 velocity
6 0
3 years ago
When the moon is waxing, it's lighted part appears
kvv77 [185]
To increase it's size

Waxing is the opposite of waning, which is to decrease.
7 0
3 years ago
Read 2 more answers
As a United States citizen, the requirement to serve on juries if called upon is considered which of the following?
ratelena [41]

Answer:

if u are caught by the jews u die

Explanation:

7 0
3 years ago
On a part-time job, you are asked to bring a cylindrical iron rod of density 7800 kg/m3, length 88.8 cm and diameter 2.30 cm fro
vichka [17]

Answer:

w = 28.25 N

Explanation:

To do this, we need to use two expressions.

First, to calculate the weight of any object, we use the 2nd law of newton. In this case, the weight is:

w = m*g  (1)

However we do not have the mass of the rod. We need to calculate that. To calculate the mass, we'll use the expression of density which is:

d = m/V  

From here, we solve for mass:

m = d * V   (2)

Finally, we can know the volume of the rod, because is cylindrical, therefore, the volume of a cylinder is:

V = π * r² * h   (3)

So, in resume, we need to solve for the volume of the rod, then, the mass ans finally the weight. Let's calculate the volume of the rod, converting the units of centimeter to meters, just dividing by 100:

diameter = 2.3 cm ---> radius = 2.3/2 = 1.15 cm -----> 0.0115 m

Length or height = 88.8 cm ----> 0.888 m

Replacing in (3):

V = π * (0.0115)² * 0.888

V = 3.69x10⁻⁴ m

Now, let's use (2) to calculate the mass:

m = 7800 * 3.69x10⁻⁴

m = 2.88 kg

Finally for the weight, we'll use expression (1):

w = 2.88 * 9.81

<h2>w = 28.25 N</h2><h2>And this is the weight of the rod.</h2>
4 0
3 years ago
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