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loris [4]
3 years ago
7

Which type of energy is emitted from earth to the atmosphere? *?

Physics
1 answer:
notsponge [240]3 years ago
7 0
Infrared radiation - Greenhouse gases in the atmosphere absorb most of the earth's emitted infrared radiation which heats the lower atmosphere
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Why electrons flow in a wire when connected to a battery?
vesna_86 [32]

Answer:

The metal atoms in the wire can't move, but their outer electrons can. The force pushes those electrons and they move to further parts of the wire, trying to reach the other end. As the electrons move away, new electrons flow into the wire through the battery to take their place.

Explanation:

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3 years ago
Heat from Earth's interior causes convection currents in Earth's _________.
Bas_tet [7]
The convection currents would come from the exterior core and they would travel through the mantle and eventually through the core
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Wire 1 has a resistance R1. Wire 2 is made of the same material, with length 1/2 as long and diameter 1/4. What is the resistanc
hodyreva [135]

-- reduce the length of a wire to 1/2 . . . cut the resistance in half

-- reduce the diameter to 1/4 . . . reduce the cross-section area by (1/4²) . . . increase the resistance by 16x .

-- R2 = (R1) · (1/2) · (16)  =  8 · R1

<em>-- R2 / R1  =  8</em>

5 0
3 years ago
What's a streak plate?
andrew-mc [135]
An unglazed piece of porcelain, used to test the characteristic streak of minerals by rubbing the mineral across the tile. Streak plates have a hardness of about 6.5 on the Mohs scale and cannot be used for testing harder minerals.
3 0
3 years ago
Tamsen is interested in history, and read that because of its regular period, the pendulum constituted the basis of the most acc
geniusboy [140]

We will apply the concept of period in a pendulum, defined as the product between 2\pi by the square root of the length over gravity, this is mathematically

T = 2\pi \sqrt{\frac{L}{g}}

Here,

T = Period

L = Length

g = Acceleration due to gravity

For the period to be 1 second, then we must look for the necessary length for such a requirement so

1 = 2\pi \sqrt{\frac{L}{9.8}}

(\frac{1}{2\pi})^2 = \frac{L}{9.8}

L = 9.8(\frac{1}{2\pi})^2

L = 0.2482m

The meter's length would be slight less than one-fourth of its current length. Also, the number of significant digits depends only on how precisely we know g, because the time has been defined to be exactly 1s.

Therefore the correct answer is C.

3 0
3 years ago
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