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vredina [299]
3 years ago
8

A piece of silver metal has a mass of 3.687 grams. If the density of silver is 10.5 g/cm, what is the volume of the silver?​

Chemistry
1 answer:
GenaCL600 [577]3 years ago
3 0

Answer:

Volume = (0.62 m)^3

Explanation:

If the density of silver is 10.5 g/cm, the volume of the silver is (0.62 m)^3.

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What is the representative particle for barium chloride?
KIM [24]
Barium chloride is salt with ionic bonds. Barium chloride contains one barium cations (charge of ion is 2+) and two chlorine anions (charge for ion is 1-).
The representative particle<span> of an ionic compound is its formula unit (</span>lowest whole number ratio of ions in an ionic compound), for barium chloride that is BaCl₂.
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What do they mean by “zigzag line” ?
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Why do Group 12 elements have different properties than Group 13<br> elements?
blagie [28]
Group 12 Elements have two valence electrons while Group 13 Elements have three valence electrons.
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6 0
3 years ago
A gas mixture contains 3.0 mol of hydrogen (H2) and 7.3 mol of nitrogen (N2). The total pressure of the mixture is 304 kPa. What
Inga [223]

Answer:

Mole fraction H₂ = 0.29

Partial pressure of H₂ → 88.5 kPa

Explanation:

You need to know this relation to solve this:

Moles of a gas / Total moles = Partial pressure of the gas / Total pressure

Total moles = 3 mol + 7.3 mol → 10.3 moles

Mole fraction H₂ → 3 moles / 10.3 moles = 0.29

Mole fraction = Partial pressure of the gas / Total pressure

0.29 . 304 kPa = Partial pressure of H₂ → 88.5 kPa

5 0
3 years ago
When electromagnetic radiation of wavelength 300nm falls on the surface of sodium electrons are emitted with a KE of 1.68 * 10 5
gtnhenbr [62]

Answer:

3.83 × 10⁻¹⁹ J;  518 nm  

Step-by-step explanation:

The equation for the <em>photoelectric effect</em> is

hf = Φ + KE  

<em>Data: </em>

λ = 300 nm = 300 × 10⁻⁹ m

KE = 1.68 × 10⁵ J/mol

Calculations:

Part 1. Minimum energy to remove an electron

(a) Calculate the <em>energy of the photon</em>

fλ = c  

 f = c/λ     Divide each side by λ

E = hf

E = hc/λ

E = (6.626× 10⁻³⁴ × 2.998 × 10⁸)/(300 × 10⁻⁹)

E = 6.622 × 10⁻¹⁹ J

(b) Calculate the <em>KE of one electron</em>

KE = 1.68 × 10⁵ × 1/(6.022 × 10²³)

KE = 2.790 × 10⁻¹⁹ J

(c) Calculate the work function

hf = Φ + KE     Subtract KE from each side

Φ = 6.622 × 10⁻¹⁹  - 2.790 × 10⁻¹⁹

Φ = 3.83 × 10⁻¹⁹ J

The minimum energy to remove an electron from a sodium atom

is 3.83 × 10⁻¹⁹ J.

Part 2. Maximum wavelength to remove an electron

The photon must have just enough energy to overcome the work function and leave the electron with zero kinetic energy.

    E = Φ

hc/λ = Φ                      Multiply each side by λ

  hc = Φ λ                   Divide each side by Φ

   λ = hc/ Φ

   λ = (6.626 × 10⁻³⁴ × 2.998 × 10⁸)/(3.83 × 10⁻¹⁹)

   λ = 5.18 × 10⁻⁷ m     Convert to nanometres

   λ = 518 nm

The maximum wavelength that will cause an electron to move is 518 nm.

6 0
3 years ago
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