Answer:
Final temperature = T₂ = 328.815 K
Explanation:
Given data:
Given energy = 980 KJ = 980×1000= 980000 J
Volume = 6.2 L
Initial temperature =T₁= 291 K
Specific heat of water = 4.18 j /g .K
Final temperature = T₂ = ?
Formula:
Q = m. c . ΔT
ΔT = T₂ - T₁
we will first convert the litter into milliliter
6.2 × 1000 = 6200 mL
It is given in question that
1 mL = 1 g
6200 mL = 6200 g
Now we will put the values in formula,
Q = m. c . (T₂ - T₁)
980000 j = 6200 g . 4.18 j /g .K . (T₂ - 291 K)
980000 j = 25916 j/ k . (T₂ - 291 K)
980000 j / 25916 j/ k = T₂ - 291 K
37.8145 K + 291 K =T₂
T₂ = 328.815 K
X: 1S²2S²2P⁶
Y: 1S²2S²2P⁶3S²3P⁶
The statement which is most likely correct about the two elements is
They will not react because both have a complete outermost shell and are stable.
<u><em>Explanation</em></u>
The P orbital can hold a maximum of 6 electrons,therefore the 2P orbital for x and 3P orbital for Y which are outermost subshell are fully filled .
This make element Y and x stable since they cannot react either by gaining or losing electrons.
Answer:
A
Explanation:
particles are frozen and hence will vibrate in their fixed positions
Answer:
Empirical formula is C₃H₃O.
Explanation:
Given data:
Mass of compound = 0.519 g
Mass of CO₂ = 1.24 g
Mass of H₂O = 0.255 g
Empirical formula = ?
Solution:
%age of C,H,O
C = 1.24 g/0.519 × 12/44 ×100 = 65.5%
H = 0.255 g/0.519 × 2.016/18 ×100 = 5.6%
O = 100 - (65.5+5.6)
O = 28.9%
Number of gram atoms of H = 5.6 / 1.01 = 5.5
Number of gram atoms of O = 28.9 / 16 = 1.81
Number of gram atoms of C = 65.5 / 12 = 5.5
Atomic ratio:
C : H : O
5.5/1.81 : 5.5/1.81 : 1.81/1.81
3 : 3 : 1
C : H : O = 3 : 3 : 1
Empirical formula is C₃H₃O.
Ang answer at Assume the following: mass defect =5.0531 x 10 - 29 kilograms. Use E =mc2, with c =3 x 108 m/s. At isa pa ang sa got mag aral ng mabuti kyo ah
