How many grams of Ca(OH)2 are needed to produce 500ml of 1.66 M Ca(OH)2 solution

1 answer:

3 0

First, determine how many moles are present in solution. Once you have this, you can convert to grams to find the number of grams in your final solution.

To determine how many moles are in your solution, simply multiply Molarity by Volume. Molarity is expressed in units of moles/liter, so your liters will cancel out leaving you with moles. Just ensure that your units of volume are all expressed in liters before attempting the calculation:

1.66 mol/L x 0.5 L = 0.83 mol

To determine how many grams are present in a mole, you will need the molar mass of Ca(OH)2. Using a periodic table, we can determine the molar mass by adding together 1 Ca, 2 O, and 2 H. This turns out to be approximately (40+32+2) = 74 g/mol. Again, paying attention to units we can see that by multiplying moles by molar mass, we will cancel out moles and leave us with grams.

0.83 mol x 74 g/mol = 61.42 grams of Ca(OH)2

Answer: 61.42 grams of Ca(OH)2 are needed to produce 500 mL of a 1.66 M solution.

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The bond angles in SCl2 are expected to be Multiple Choice a little more than 109.5°. 109.5°. 120°. a little less than 109.5°. 1

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Answer:

a little less than 109.5°

Explanation:

SCl2 has four regions of electron density around the central atom of the molecule. This implies that it has a tetrahedral electron domain geometry with an expected bond angle of 109.5° according to valence shell electron pair repulsion theory.

However, there are two lone pair of electrons on the central atom of the molecule which decreases the bond angle a little less than 109.5° owing to repulsion between electron pairs.

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Jill then wrote the formulas for all the possible compounds that sodium can form with the other ions. What formulas did she writ

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Explanation:

Sodium has atomic number of 11 and its electronic configuration is given by:

$[Na]=1s^22s^22p^63s^1$

The nearest stable electronic configuration to sodium is of the neon. So, in order to attain stability of noble gas it will loose its single electron.

$Na\rightarrow Na^++1e^-$

$[Na^+]=1s^22s^22p^63s^0$

Sodium has single valency that is 1.

Let nbe the valency of the ion 'X'

By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

$Na_nX_1$