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Alexandra [31]
2 years ago
13

How many grams of Ca(OH)2 are needed to produce 500ml of 1.66 M Ca(OH)2 solution

Chemistry
1 answer:
bogdanovich [222]2 years ago
3 0
First, determine how many moles are present in solution. Once you have this, you can convert to grams to find the number of grams in your final solution.

To determine how many moles are in your solution, simply multiply Molarity by Volume. Molarity is expressed in units of moles/liter, so your liters will cancel out leaving you with moles. Just ensure that your units of volume are all expressed in liters before attempting the calculation:

1.66 mol/L x 0.5 L = 0.83 mol

To determine how many grams are present in a mole, you will need the molar mass of Ca(OH)2. Using a periodic table, we can determine the molar mass by adding together 1 Ca, 2 O, and 2 H. This turns out to be approximately (40+32+2) = 74 g/mol. Again, paying attention to units we can see that by multiplying moles by molar mass, we will cancel out moles and leave us with grams.

0.83 mol x 74 g/mol = 61.42 grams of Ca(OH)2

Answer: 61.42 grams of Ca(OH)2 are needed to produce 500 mL of a 1.66 M solution.
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AlladinOne [14]

They both have two electron shells

<h3>Further explanation</h3>

The period 2 element lies in the second row of the periodic system.

Consists of the elements: lithium, beryllium, boron, carbon, nitrogen, oxygen, fluorine, and neon

  • Lithium (Li)

atomic number : 3

electron configuration : [He] 2s¹

atomic number = number of proton=number of electron(in neutral atom)

So Li have 3 protons and 3 electrons

Because it fills the 2s orbital it has 2 shells

  • Oxygen (O)

atomic number : 8

electron configuration :  [He] 2s²2p⁴

So O have 8 protons and 8 electrons

Because it fills the 2s and 2p orbital it has 2 shells

So Lithium (Li) and Oxygen (O) are both have two electron shells

6 0
3 years ago
An atom of oxygen has atomic of 8 and a mass number of 18. How many of each type of subatomic particle doe it contain?
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Electrons = 8

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Neutrons = 10.
7 0
3 years ago
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Evgesh-ka [11]

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3 years ago
Glucose, C6H12O6,C6H12O6, is used as an energy source by the human body. The overall reaction in the body is described by the eq
Ilia_Sergeevich [38]

Answer:

Mass of oxygen = 61.824 g

Mass of carbon dioxide = 85.01 g

Explanation:

Given data:

Mass of glucose = 58 g

Mass of carbon dioxide = ?

Mass of oxygen = ?

Solution:

First of all we will write the balanced chemical equation,

C₆H₁₂O₆  + 6O₂       →    6CO₂  + 6H₂O

Moles of glucose:

Number of moles = mass / molar mass

Number of moles = 58 g/180 g/mol

Number of moles =  0.322 mol

Now we compare the moles of oxygen with glucose from balance chemical equation.

                             C₆H₁₂O₆          :              O₂  

                                    1                :              6

                                    0.322       :              0.322×6 = 1.932 mol

Mass of oxygen:

Mass of oxygen = number of moles × molar mass

Mass of oxygen =  1.932 mol × 32 g/mol

Mass of oxygen =  61.824 g

Now we compare the moles of carbon dioxide with moles of glucose and oxygen.

                              C₆H₁₂O₆            :              CO₂

                                   1                   :                 6

                                  0.322           :           0.322×6 = 1.932 mol

                                   

                                 O₂                    :                 CO₂

                                  6                     :                  6

                                 1.932                :                  1.932

Mass of carbon dioxide;

mass of carbon dioxide = number of moles × molar mass

mass of carbon dioxide =  1.932 mol × 44 g/mol

mass of carbon dioxide =  85.01 g

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Answer:

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