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liraira [26]
4 years ago
13

A 25-mL solution of H2SO4 is completely neutralized by 18 mL of 1.0M NaOH. What is the concentration of the H2SO4?H2SO4(aq) +2Na

OH(aq) → Na2SO4(aq) + 2H2O(l)
Chemistry
1 answer:
cricket20 [7]4 years ago
4 0
1) Balanced chemical reaction

     H2SO4 (aq) + 2NaOH(aq) ----> Na2SO4(aq) + 2 H2O(liq)

2) Molar ratios

1 mol H2SO4 : 2 mol NaOH : 1 mol Na2SO4

3) Number of moles of NaOH


M = n / V => n = M * V = 1.0 M * 0.018 liter = 0.018 mol
of NaOH.


4) Determine the number of moles of H2SO4 using proportionality

1 mol H2SO4 / 2 mol NaOH = x / 0.018 mol NaOH

Solve for x:

x = 0.018 mol NaOH * 1 mol H2SO4 / 2 mol NaOH =0.009 mol H2SO4


5) Calculate the molarity using 0.009 mol and 25 mililiters

M = n / V = 0.009 mol / 0.025 liter = 0.36 M 

Answer: the concentration of the H2SO4 is 0.36 M



 


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An isotope has a half-life of 10 minutes. after 20 minutes, what percentage of the original nuclei remain?
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by rearranging the equation,
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From (1) and (2),

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6 0
3 years ago
The reaction between ethylene and hydrogen bromide to form ethyl bromide is carried out in a continuous reactor. The product str
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Answer:

Explanation:

The first thing to do is to write out the chemical equation showing the reaction between the two chemical compounds.

C2H4 + HBr ------------------------> C2H5Br.

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So, if we have 100 mol/s ;

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Therefore, the total value of the flow rate in the feed = (HBr in feed) mol/s + (C2H4 in feed) mol/s = (58.7 + 18.3)mol/s + (58.7 + 23) mol/s =( 77 + 81.7) mol/s = 158.7 mol/s. .

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Also the feed composition in HBr and C2H4 is;

HBr = 77/158.7 = 0.4852, C2H4 = 81.7/158.7 = 0.515.

Therefore, the number of HBr in feed and C2H4 in feed = 160m/s and 200m/s respectively (approx.)

Therefore, the fraction conversion is;

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