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Tasya [4]
3 years ago
6

During the Big Bang, what were the two main chemical elements created?

Chemistry
2 answers:
Semmy [17]3 years ago
4 0
During the big band only the lightest elements were formed – hydrogen<span> and </span>helium<span> along with trace amounts of </span>lithium<span> and </span>beryllium<span>.</span>
Tasya [4]3 years ago
3 0
this is the answer I got hydrogen and helium
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How many mol are in 8.23 x 10^24 formula units of calcium carbonate
tensa zangetsu [6.8K]

Answer:

13.7 moles

Explanation:

Given data:

Number of moles calcium carbonate = ?

Formula units calcium carbonate= 8.23 × 10²⁴

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

For 8.23 × 10²⁴ formula units:

one mole = 6.022 × 10²³ formula units

8.23 × 10²⁴ formula units × 1 mole /6.022 × 10²³ formula units

13.7 moles

7 0
3 years ago
Which pictures shows the proper structure of the water molecule? Click the picture to see each choice.
Yuliya22 [10]

The third picture is the answer

Explanation:

there are 2 hydrogen atom 1 oxygen

7 0
2 years ago
Do viruses have locomotion
Dvinal [7]

Answer:

No

Explanation:

They do not have any sensing organs. They can't see, smell or move on their own. They rely on random motions from their host to move around.

5 0
3 years ago
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How can you make a solution saturated?
liubo4ka [24]
You can make a solution saturated by Adding more solute. Hope this helps, good luck. 
8 0
3 years ago
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The radius of an indium atom is 0.163 nm. If indium crystallizes in a face-centered unit cell, what is the length of an edge of
adoni [48]

<u>Answer:</u> The edge length of the unit cell is 0.461 nm

<u>Explanation:</u>

We are given:

Atomic radius of iridium = 0.163 nm

To calculate the edge length, we use the relation between the radius and edge length for FCC lattice:

a=2\sqrt{2}R

Putting values in above equation, we get:

a=2\sqrt{2}\times 0.163=0.461nm

Hence, the edge length of the unit cell is 0.461 nm

8 0
3 years ago
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