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Tasya [4]
3 years ago
6

During the Big Bang, what were the two main chemical elements created?

Chemistry
2 answers:
Semmy [17]3 years ago
4 0
During the big band only the lightest elements were formed – hydrogen<span> and </span>helium<span> along with trace amounts of </span>lithium<span> and </span>beryllium<span>.</span>
Tasya [4]3 years ago
3 0
this is the answer I got hydrogen and helium
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A hydrate of CuSO4 has a mass of 12.98 g before heating. After heating, the mass of the anhydrous compound is found to be 9.70 g
lukranit [14]
Explanation of the strategy: 1) calculate the mass of water and convert to number of moles, 2) convert the mass of anhydrous CuSO4 to moles, and, 3)calculate the mole ratio of water to CuSO4 anhydrous

1) Calculate the mass of water:

mass of water = mass of the hydrate CuSO4 - mass of the anhydrous compound

mass of water = 12.98 g - 9.70 g = 3.28g

2) Calculate the number of moles of water

number of moles = mass in grams / molar mass

molar mass of water = 18.01 g/mol

number of moles of water = 3.28 g / 18.01 g/mol = 0.182 mol

3) Calculate the number of moles of CuSO4 anhydrous

number of moles = mass in grams / molar mass

molar mass of Cu SO4 = 159.6 g/mol

number of moles of CuSO4 = 9.70g / 159.6 g/mol = 0.0608 moles

4) Calculate the ratio moles of water / moles of CuSO4

ratio = moles of water / moles of CuSO4 = 0.182 / 0.0608 = 2.99 ≈ 3

Therefore the molecular formula is CuSO4 . 3H2O

Name: copper(II) sulfate trihydrate.
4 0
3 years ago
Read 2 more answers
Any mixture that is heterogeneous on a microscopic level is a
Nadya [2.5K]
Solution is the answer.
5 0
3 years ago
Your dad is working on creating a brick border for the lake in your backyard each brick has a mass of 100 g and a volume of 20 c
wel

Answer:

5000kg/m³

Explanation:

density=mass/volume

d=m/v

d=100/20

=5g/cm³

g/cm³*1000=kg/m³

5g/m³*1000=5000kg/m³

4 0
2 years ago
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What volume of 0.160 m li2s solution is required to completely react with 130 ml of 0.160 m co no3 2?
Over [174]
The  volume  of  0.160    m   Li2S  solution  required  to  completely  react  with  130 ml  of 0.160  CO(NO3)2  is calculated   as  below

write the  reacting  equation

Co(NO3)2 +  Li2S = 2LiNO3  +  COS

find the    moles  of CO(NO3)2  = molarity  x  volume

=  130 ml  x  0.160=20.8  moles

since the reacting moles between CO(NO3)2  to LiS  is   1:1  the  moles of LiS  is  also  20.8  moles

volume  of Lis  is  therefore =  moles of Lis/ molarity  of LiS

=  20.8/0.160 =  130 Ml
3 0
3 years ago
How do I complete this column graph of the number of conductors vs the number of insulators
Vikentia [17]

Answer:

sorry but i am doing this for point

Explanation:

how do I complete this column graph of the number of conduct vs the number of

4 0
3 years ago
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