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Zanzabum
4 years ago
9

Use the periodic table and the above figure.

Chemistry
2 answers:
nevsk [136]4 years ago
8 0

Answer:

6

Explanation:

Carbon is the 6th element of the periodic table and the atomic number is the same as the amount of electrons it has.

Tomtit [17]4 years ago
6 0

Answer:

4

Explanation:

observing the electronic configuration for the Carbon atom shown in the periodic table:

[He] 2s² 2p²

Therefore, it can be seen that at level s and level p it has two electrons per level to form chemical bonds, which gives it a total of 4 available electrons.

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Who invented plutonium
wlad13 [49]
Joseph Kennedy 
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Edwin Mattison McMillan
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5 0
3 years ago
Read 2 more answers
The mass of an average blueberry is 0.75 g and the of am automoblie is 2.0 x 10 to the 3 Kg. Find the number of automobiles whos
Paul [167]

Answer : The number of automobiles needed are, 2.26\times 10^{17}

Explanation :

First we have to calculate the mass of blueberries.

As, 1.0 mole of blueberries contains 6.022\times 10^{23} blueberries

So, 0.75 grams of blueberries contains 0.75g\times 6.022\times 10^{23}=4.52\times 10^{23}g blueberries

Mass of blueberries = 4.52\times 10^{23}g

Now we have to calculate the number of automobiles needed.

Number of automobiles needed = \frac{4.52\times 10^{23}g}{2.0\times 10^{3}kg}

Number of automobiles needed = \frac{4.52\times 10^{23}g}{2.0\times 10^{3}\times 10^{3}g}

Number of automobiles needed = 2.26\times 10^{17}

Thus, the number of automobiles needed are, 2.26\times 10^{17}

8 0
3 years ago
Iodine-131 is a radioactive isotope that is used in the treatment of cancer of the thyroid. The natural tendency of the thyroid
Finger [1]

Answer:

a) Binding Energy = 1084.266 MeV

b) Binding energy per nucleon = 8.28 MeV

Explanation:

Binding Energy, BE = \triangle M * 931.5

Where ΔM = Mass defect of Iodine-131

The mass of iodine-131 = 130.906124 u.

Number of protons in Iodine-131 = 53

Number of neutrons in Iodine-131 = 78

Mass of a proton = 1.007276 u

Mass of neutron = 1.008664 u

Total mass of the 53 protons in Iodine-131 = (53*1.007276)

Total mass of the 53 protons in Iodine-131 =  53.39 u

Total mass of the 78 protons in Iodine-131 = (78*1.008664)

Total mass of the 78 protons in Iodine-131 = 78.68 u

\triangle M = (53.39 + 78.68) - 130.906124\\\triangle M = 1.164 u

Binding Energy = 1.164 * 931.5

Binding Energy = 1084.266 MeV

b) Binding Energy per nucleon

The mass of the nucleon of iodine 131 = 130.906124

Binding Energy per nucleon =  1084.266/130.906124

Binding energy per nucleon = 8.28 MeV

5 0
4 years ago
An unknown quantity of methane gas, CHA, is held in a 2.00-liter container at 77°C. The pressure inside the container is 3.00 am
kolbaska11 [484]

Answer:

0.21\text{ mol}

Explanation:

Here, we want to calculate the number of moles of methane in the container

From the ideal gas law:

\begin{gathered} PV\text{ = nRT} \\ n\text{ = }\frac{PV}{RT} \end{gathered}

where:

P is the pressure inside the container which is 3 atm

V is the volume of the container which is 2 L

R is the molar gas constant which is 0.0821 Latm/mol.k

T is the temperature in Kelvin (we convert the temperature in Celsius by adding 273 : 273 + 77 = 350 K)

n is the number of moles that we want to calculate

Substituting the values, we have it that:

n=\text{ }\frac{3\times2}{0.0821\text{ }\times350}\text{ = 0.21 mol}

6 0
1 year ago
Butane, C4H10 burns in oxygen. How many grams of water vapor, H2O, are produced by the combustion of 580 grams of butane at stan
zepelin [54]

Answer:

The answer to your question is 900 g of water vapor

Explanation:

Data

mass of H₂O = ?

mass of butane = 580 g

Balanced chemical reaction

             2C₄H₁₀ + 13O₂  ⇒  8CO₂  +  10H₂O

Process

1.- Calculate the molar weight of butane and water

Butane (C₄H₁₀) = 2[(12 x 4) + (1 x 10)]

                         = 2[48 + 10]

                         = 2[58]

                         = 116 g

Water (H₂O) = 10[(1 x 2) + (1 x 16)]

                    = 10[2 + 16]

                    = 10[18]

                    = 180 g

2.- Use proportions and cross multiplication to find the mass of water vapor

             116 g of butane ------------- 180 g of water

             580 g of butane  ----------  x

                x = (580 x 180) / 116

                x = 900 g of water vapor

3 0
3 years ago
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