Answer:
approximately 0.2 days
Step-by-step explanation:
Flow is defined as:
Q = V/t
where Q is flow, V is volume, and t is time
Let's call Vr to the volume of the reservoir, then for the first channel:
Q1 = Vr/t1
Replacing with t1 = 1/3 of day:
Q1 = Vr/(1/3) = 3*Vr
Similarly, or the other channels:
Q2 = Vr/1 = Vr
Q3 = Vr/(2 1/2) = 2/5*Vr
Q4 = Vr/3
Q5 = Vr/5
When all channels are open, the time needed to fill the reservoir is:
Vr = t*(Q1 + Q2 + Q3+ Q4 + Q5)
Replacing with the previous equivalences:
Vr = t*(3*Vr + Vr + 2/5*Vr+ Vr/3 + Vr/5)
Vr = t*4.93*Vr
1/4.93 = t
0.2 = t
The probability of the sample is 0.5 or 50%
<u>Explanation:</u>
Given:
Mean, μ = 20
Standard deviation, δ = 1.3
Probability of sample being less than 20.1 = ?
P (x < 20.1) = 20.1 - μ / δ √n
P (x < 20.1) = 
= 0.0098
P( x < 20.1) = P(z < 0.0098)
P (z < 0.0098) = 0.5
The value of P is found out using a z score table.
Therefore, probability of the sample is 0.5 or 50%
Get x on its own side
7+x-15=2 2/3
+15 +15
7+x=17 2/3
-7 -7
x= 10 2/3
Hope I helped
x+y= 4 (-2)
3x+2y = 9
-2x -2y = -8
3x +2y = 9
x = 1
1+y =9
y = 9-1
y =8
