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Crazy boy [7]
3 years ago
6

Keaton is asked to solve the following physics problem:

Physics
1 answer:
RideAnS [48]3 years ago
5 0

Answer:

The answer is C "think about the problem first, systematically consider all factors, and form a hypothesis"

Explanation:

In physics there is some basic fomula that sir Isacc Newton proposed under the topic of motion. The three formulas are below;

<em>1) v=u+at</em>

<em>2)v^2=u^2+2as</em>

<em>3)s=ut+(1/2)(at^2)</em>

the variables are explained below;

u= initial velocity of the body

a=acceleration/Speed of the body

t= time taken by the body while travelling

s= displacement of the body.

Therefore to solve keatons problem, the factors(variables) in the formulas above need to be systematically considered. Since the ball was dropped from the top of the building, the initial velocity is 0 because the body was at rest. Also the acceleration will be acceleration due to gravity (9.8m/s^2)

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Answer:

I think B is the answer

Explanation:

I think this cause a maid always cleans the house and might be awake at night

3 0
2 years ago
Which statement best describes ionic bonding?
FromTheMoon [43]
D. Ionic bonding is when electrons are transferred. When they're shared, it is covalent. In order to take an electron from a full valence electeon shell, you would need a massive amount of energy.
4 0
3 years ago
Read 2 more answers
A wire of 1mm diameter and 1m long fixed at one end is stretched by 0.01mm when a lend of 10 kg is attached to its free end.calc
Otrada [13]

Answer:

E = 1.25×10¹³ N/m²

Explanation:

Young's modulus is defined as:

E = stress / strain

E = (F / A) / (dL / L)

E = (F L) / (A dL)

Given:

F = 10 kg × 9.8 m/s² = 98 N

L = 1 m

dL = 10⁻⁵ m

A = π/4 (0.001 m)² = 7.85×10⁻⁷ m²

Solve:

E = (98 N × 1 m) / (7.85×10⁻⁷ m² × 10⁻⁵ m)

E = 1.25×10¹³ N/m²

Round as needed.

5 0
3 years ago
In which situation does the reactive force between two colliding objects cause a physical change? (1 point)
jarptica [38.1K]

Answer:

a baseball player swinging a bat and hitting a baseball, causing the bat to shatter

Explanation

took the test, hope it helps

8 0
2 years ago
How far apart are two conducting plates that have an electric field strength of 4. 4 kv/m between them, if their potential diffe
IRINA_888 [86]

Conducting plates will be 3.75 m apart if an electric field strength of 4. 4 kV/m between them, if their potential difference is 15 kV

The potential difference, also referred to as voltage difference between two given points is the work in joules required to move one coulomb of charge from one point to the other. The SI unit of voltage is the volt. Volt Formula.

In a simple parallel-plate capacitor, a voltage applied between two conductive plates creates a uniform electric field between those plates. The electric field strength in a capacitor is directly proportional to the voltage applied and inversely proportional to the distance between the plates.

E = V/d

E = Electric field strength

d = distance between the plates

V = potential difference

Electric field strength = 4 kV/m

Potential difference  =  15 kV

d = V / E =  15 kV / 4 kV/m

  = 3.75 m

To learn more about capacitor here

brainly.com/question/17176550

#SPJ4

6 0
2 years ago
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