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3 years ago

9

The term ampacity is defined as the _____ current, in amperes, that a conductor can carry continuously under conditions of use w

ithout exceeding its temperature rating.

1 answer:

White raven [17]3 years ago

5 0

Answer:

The maximum current, in amperes, that a conductor can carry continuously under the conditions of abuse without exceeding its temperature rating.

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1. Three vehicles are traveling at the same speed in the same direction on a 1 point

rusak2 [61]

9514 1404 393

Answer:

The front of the black car

Explanation:

The position -21 is shown on the diagram at the front of the white van. The reference point is the position 0, which is shown on the diagram as the front of the black car.

4 0

3 years ago

Read 2 more answers

An object is moving at 5 m/s and a height of 4m. If the object has a mass of 5kg what is it mechanical energy

Lady bird [3.3K]

Answer: 258.7 J

Explanation:

E=Ek+Ep

E=m*V²/2 +mGh

E=5*25/2+5*9.81*4

E=62.5+196.2

E=258.7 J

3 0

3 years ago

One point charge has a magnitude 5.4x10-7 C. A second charge 0.25 meters away has a magnitude of 1.1x10-17 C. What is the electr

choli [55]

The electric force on the charges will be equal and opposite in nature and the magnitude will be 8.5536 × 10⁻¹³ Newton.

Formula for electrostatic force is F = ( K q1 q2 )/ r²

where q1 and q2 represent the charges and r represents the distance between them and the value of K is 9 × 10⁹.

In question we have given

value of q1 = 5.4 x 10⁻⁷ C

value of q2 = 1.1 x 10⁻¹⁷ C

distance between the (r) = 0.25 m

Applying the formula

F = ( K x (5.4 x 10-7) x (1.1x10-17) )/ 0.25²

F = ( (9 × 10⁹ ) x (5.4 x 10-7) x (1.1x10-17) )/ 0.25²

F = ( (9 × 5.4 × 1.1) × ( 10⁹ × 10⁻⁷ x 10⁻¹⁷) )/ ( 6.25 × 10⁻² )

F = ( 53.46 × 10⁻¹⁵) / ( 6.25 × 10⁻² )

F = 8.5536 × 10⁻¹³ Newton

Electrostatic force = 8.5536 × 10⁻¹³ Newton

So, The point charges are possessing equal and opposite electrostatic force of magnitude 8.5536 × 10⁻¹³ Newton.

Learn more about Electrostatic Force here:

brainly.com/question/23121845

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8 0

2 years ago

Purpose of slip rings in ac generators

Leni [432]

I hope this helps you

6 0

3 years ago

An electrical motor spins at a constant 1975.0 rpm. If the armature radius is 7.112 cm, what is the acceleration of the edge of

stealth61 [152]

Answer:

Option D is the correct answer.

Explanation:

Since value of angular acceleration is constant, the body has only centripetal acceleration.

Centripetal acceleration

$a=\frac{v^2}{r}=\frac{(r\omega )^2}{r}=r\omega ^2$

We have radius = 7.112 cm = 0.07112 m

Frequency, f = 1975 rpm = 32.92 rps

Angular frequency, ω = 2πf = 2 x π x 32.92 = 206.82 rad/s

Substituting in centripetal acceleration equation,

$a=r\omega ^2=0.07112\times 206.82^2=3042.17m/s^2$

Option D is the correct answer.

3 0

4 years ago