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3 years ago

6

Why do some athletes engage in cross training

1 answer:

tigry1 [53]3 years ago

4 0

Answer; Cross training enables your body to recuperate faster from injuries, in some cases because other exercises can directly improve the condition caused by your regular activity. For example, Achilles tendonitis, caused by overuse, can be improved by eccentric strengthening of the calf muscles.Explanation:

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A damped mass/spring system takes 14.0 s for its amplitude of the oscillator to decrease by a factor of 9. By what factor does t

fiasKO [112]

Answer:

The correct answer is "0.246".

Explanation:

Given that the amplitude is decreased by a factor of 9, then

$A \rightarrow (A-\frac{A}{9} )$

$A \rightarrow \frac{8A}{9}$

As we know,

Energy will be:

⇒ $E_{1}=\frac{1}{2}KA^2$

and,

⇒ $E_{2}=\frac{1}{2}K(\frac{8A}{9} )^2$

$=\frac{64KA^2}{162}$

⇒ $\Delta E=E_1-E_2$

On putting the estimated values, we get

$=\frac{1}{2}KA^2-\frac{64KA^2}{162}$

⇒ $\frac{\Delta E}{E}=\frac{\frac{20}{162}KA^2}{\frac{1}{2}KA^2}$

$=\frac{40}{162}$

$=0.246$

3 0

3 years ago

Try this out. Use a calculator!

Maslowich

Just subsitute and easy
v=55m/s
m=100kg
KE=(0.5)(100kg)(55m/s)^2
KE=(50kg)(3025 m^2/s^2)
KE=151250 J
2nd option

6 0

3 years ago

The sun rotates once in 25.05 days. That is 601.2 hours. so the sun's rotational speed is 0.0017 rotations per hour. what is the

Margaret [11]

Answer:

$v=2019.09\ m.s^{-1}$

Explanation:

Given:

time taken by the sun to complete one revolution, $t=601.2\ hr$

radial distance of the sunspot, $r=6.955\times 10^8\ m.s^{-1}$

<u>Therefore, angular speed of rotation of sun:</u>

$\omega=\frac{2\pi}{601.2\times 3600} \ rad.s^{-1}$

<u>Now the tangential velocity of the sunspot can be given by:</u>

$v=r.\omega$

$v=6.955\times 10^8\times \frac{2\pi}{601.2\times 3600}$

$v=2019.09\ m.s^{-1}$

4 0

3 years ago

A $100 cart is moving down an inclined plane at 1.30 m/s. The cart collides with a stationary object and rebounds with a speed o

Rasek [7]

Answer:

0.65 kg*m/s and 0.165 kg*m/s

Explanation:

Step one:

given data

mass m= 0.5kg

initial velolcity u=1.3m/s

final velocity v= 0.97m/s

Required

The change in momentum

Step two:

We know that the expression for impulse is given as

Ft= mv

Ft= 0.5*1.3

Ft= 0.65 kg*m/s

The expression for the change in momentum is given as

P= mΔv

substitute

Pt= 0.5*(1.3-0.97)

Pt= 0.5*0.33

Pt=0.165 kg*m/s

7 0

3 years ago

For which optical devices does d sometimes have a positive value

Vlad [161]

Answer:

B) A & C

Explanation:

8 0

3 years ago