A stone tumbles into a mine shaft strikes bottom after falling for 3.8 seconds. How deep is the mine shaft

Physics

1 answer:

stepladder [879]3 years ago

7 0

Answer:

70.8m

Explanation:

Given parameters:

Time of fall = 3.8s

Unknown:

Depth of the mine = ?

Solution:

To solve this problem, we use the appropriate motion equation as shown below;

S = ut + $\frac{1}{2}$ at²

S is the depth

u is the initial velocity = 0m/s

t is the time taken

a is the acceleration due to gravity

Now insert the parameters and solve;

Since u = 0;

S = $\frac{1}{2}$ at² = $\frac{1}{2}$ x 9.8 x 3.8² = 70.8m

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