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3 years ago

Taden has found a table of the atmospheric layers of the Sun. However, he can’t make out the names of the layers in the chart.

2 answers:

4 0

The sun is a ball of hot gases containing different kinds of elements at different cores. It has a very high temperature that radiates all throughout the Milky Way galaxy. The sun has three main parts; photosphere, chromospheres and corona. The outer core of a star located at the chromospheres contains mostly of hydrogen. Inside the hydrogen is helium then carbon, oxygen, neon, magnesium silicon and the inert gas. The photosphere is scattered by the loose electrons in the corona’s plasma.

Lina20 [59]3 years ago

4 0

Answer: A Photosphere, B Chromosphere, C Corona

Explanation:

By process of elimination, I know that the outermost layer is the Corona.

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A crate lies on a plane tilted at an angle θ = 22.5 ∘ to the horizontal, with μk = 0.19.

ValentinkaMS [17]

A) $2.03 m/s^2$

Let's start by writing the equation of the forces along the directions parallel and perpendicular to the incline:

Parallel:

$mg sin \theta - \mu_k R = ma$ (1)

where

m is the mass

g = 9.8 m/s^2 the acceleration of gravity

$\theta=22.5^{\circ}$

$\mu_k = 0.19$ is the coefficient of friction

R is the normal reaction

a is the acceleration

Perpendicular:

$R-mg cos \theta =0$ (2)

From (2) we find

$R=mg cos \theta$

And substituting into (1)

$mg sin \theta - \mu_k mg cos \theta = ma$

Solving for a,

$a=g sin \theta - \mu_k g cos \theta = (9.8)(sin 22.5)-(0.19)(9.8)(cos 22.5)=2.03 m/s^2$

B) 5.94 m/s

We can solve this part by using the suvat equation

$v^2-u^2=2as$

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement

Here we have

v = ?

u = 0 (it starts from rest)

$a=2.03 m/s^2$

s = 8.70 m

Solving for v,

$v=\sqrt{u^2+2as}=\sqrt{0+2(2.03)(8.70)}=5.94 m/s$

6 0

3 years ago

Upthrust given by Water to the body

erica [24]

Answer:

According to Archimedes principle the upthrust on the body is equal to the weight of the water displaced by the body. ... Here, the mass would be the net difference in the weight of the object.

7 0

3 years ago

A 92.0-kg skydiver falls straight downward with an open parachute through a vertical height of 325 m. The skydiver's velocity re

natka813 [3]

Answer: Workdone293.02KJ

Explanation: The equation to use to calculate Workdone = Change in KE + Change in PE

Assuming velocity is constant,KE becomes 0

Workdone= Change in PE=mg

W=92×9.8×325=293.02KJ

5 0

3 years ago

3. What average net force is required to stop a 7 kg shopping cart in 2 s if it's initially

stiv31 [10]

-12.25N

Explanation:

Given parameters:

Mass of shopping cart = 7kg

Time = 2s

initial velocity = 3.5m/s

Unknown:

Average net force required to stop the cart = ?

Solution;

According to newton's second law"acceleration of body results when a net force acts on a body".

F = ma

where F is the force

m is the mass

a is the acceleration

Acceleration is the change in velocity with time

a = $\frac{v - u}{t}$

Therefore;

F = m x $\frac{v - u}{t}$

v is the final velocity, in this case it is zero, 0

u is the initial velocity

t is the time taken

Putting in the parameters:

F = 7 x $\frac{0- 3.5}{2}$ = -12.25N

This force that will stop the cart will be directed in the opposite direction with a magnitude of 12.25N

Learn more:

Newton's law brainly.com/question/11411375

#learnwithBrainly

8 0

3 years ago

The center of mass of a 0.3 kg (non-uniform) meter stick is located at its 46-cm mark. What is the magnitude of the torque (in N

Sati [7]

Answer:

15cm

Explanation:

7 0

4 years ago