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asambeis [7]
3 years ago
7

How many grams of solid K2CO3 are needed to prepare 150. mL of a 0.50% by volume K2CO3 solution ?

Chemistry
1 answer:
serg [7]3 years ago
3 0

Answer:

0.75 g of K2CO3

Explanation:

  • To prepare 150. mL of a 0.50% by volume K2CO3 solution;
  • It means 0.5% w/v in 150 mL.
  • Therefore, there would be 0.5 of K2CO3 in 100 mL of the solution.
  • Taking the density of the solution to be equivalent to the density of water, that is, 1 g/ml.
  • The mass of the solution will be; 150 mL × 1 g/mL = 150 g

Therefore; the mass of K2CO3 will be;

  = 0.5/100 × 150 g

  = 0.75 g

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7 0
10 months ago
What is the volume of 1.56 kg of a compound whose molar mass is 81.86 g/mole and whose density is 41.2 g/ml?
hjlf

Answer:

v = 37.9 ml

Explanation:

Given data:

Mass of compound = 1.56 kg

Density = 41.2 g/ml

Volume of compound = ?

Solution:

First of all we will convert the mass into g.

1.56 ×1000 = 1560 g

Formula:

D=m/v

D= density

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