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asambeis [7]
3 years ago
7

How many grams of solid K2CO3 are needed to prepare 150. mL of a 0.50% by volume K2CO3 solution ?

Chemistry
1 answer:
serg [7]3 years ago
3 0

Answer:

0.75 g of K2CO3

Explanation:

  • To prepare 150. mL of a 0.50% by volume K2CO3 solution;
  • It means 0.5% w/v in 150 mL.
  • Therefore, there would be 0.5 of K2CO3 in 100 mL of the solution.
  • Taking the density of the solution to be equivalent to the density of water, that is, 1 g/ml.
  • The mass of the solution will be; 150 mL × 1 g/mL = 150 g

Therefore; the mass of K2CO3 will be;

  = 0.5/100 × 150 g

  = 0.75 g

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3
Murrr4er [49]

Answer:

Look at the properties of Oxygen and Silicon - the two most abundant elements in the Earth's crust - by clicking on their symbols on the Periodic Table.

Explanation:

7 0
3 years ago
Read 2 more answers
You are provided with a stock solution with a concentration of 1.0x10-5 M. You will be using this to make two standard solutions
artcher [175]

Answer:

1. V₁ = 2.0 mL

2. V₁ = 2.5 mL

Explanation:

<em>You are provided with a stock solution with a concentration of 1.0 × 10⁻⁵ M. You will be using this to make two standard solutions via serial dilution.</em>

To calculate the volume required (V₁) in each dilution we will use the dilution rule.

C₁ . V₁ = C₂ . V₂

where,

C are the concentrations

V are the volumes

1 refers to the initial state

2 refers to the final state

<em>1. Perform calculations to determine the volume of the 1.0 × 10⁻⁵ M stock solution needed to prepare 10.0 mL of a 2.0 × 10⁻⁶ M solution.</em>

C₁ . V₁ = C₂ . V₂

(1.0 × 10⁻⁵ M) . V₁ = (2.0 × 10⁻⁶ M) . 10.0 mL

V₁ = 2.0 mL

<em>2. Perform calculations to determine the volume of the 2.0 × 10⁻⁶ M solution needed to prepare 10.0 mL of a 5.0 × 10⁻⁷ M solution.</em>

C₁ . V₁ = C₂ . V₂

(2.0 × 10⁻⁶ M) . V₁ = (5.0 × 10⁻⁷ M) . 10.0 mL

V₁ = 2.5 mL

8 0
3 years ago
V=5, M=10 What is the density?
ch4aika [34]

Answer:

the answer to this question is  2 kilogram/cubic meter

Explanation:

4 0
3 years ago
#12 please! worth 40 points
Serga [27]
Okay so because of the difference in density a simple method for telling the difference between the two is to put a sample in a container with oil, because water has a higher density than the oil it would sink to the bottom but alcohol on the other hand is lighter than oil and would float on top of the oil.

However with this question I think that what you would do is use the ice to find out what the substance is, it would float on top of the liquid if it were water because the water is denser than ice but the ice would sink if it was alcohol because the alcohol is less dense than ice. 


I hope this helps you, good luck : )

3 0
3 years ago
Substance that are _________ are unable to be mixed together.
Elza [17]

Answer:

Immiscible

Explanation:

Not sure what kind of substance but this is form liquids.

8 0
2 years ago
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