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Tema [17]
3 years ago
7

Convert 27.7 kilometers to centimeters.

Chemistry
1 answer:
Stolb23 [73]3 years ago
7 0

Answer:

The correct answer is - 2770000 cm.

Explanation:

1 kilometer = 1000 meter

1 meter = 100 centimeter

1 kilometer = 100*1000 cm

1 km = 100000 cm.

then,

27.7 kilometers = 2.77 × 10^6 centimeters

So, 27.7 kilometers = 27.7 × 100000

= 2.77 × 106 or 2770000 centimeters.

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(NH4)3PO4 + Pb(NO3)4. Pb3(PO4)4 + NH4NO3
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4(NH₄)₃PO₄ + 3Pb(NO₃)₄  →  Pb₃(PO₄)₄ + 12NH₄NO₃

Explanation:

   (NH₄)₃PO₄ + Pb(NO₃)₄  →  Pb₃(PO₄)₄ + NH₄NO₃

Balancing this equation;

  We simply use a mathematical approach by solving simple algebraic equations.

       a(NH₄)₃PO₄ + bPb(NO₃)₄  →  cPb₃(PO₄)₄ + dNH₄NO₃

a,b,c and d are the coefficients that will balance the equation;

   Conserving N:    3a + 4b = 2d  equation 1

                        H:    12a = 4d

                        P;      a = 4c

                        O;      4a + 12b = 16c + 3d

Let us make a = 1;

                      c = \frac{1}{4}

                      d = 3

solving for b;

               from (i);    4b = 2d -3a = 2(3) - 3(1) = 3

                                b = \frac{3}{4}

Now multiply a, b, c and d by 4;

                   a = 4 , b = 3 , c= 1 and d = 12

                4(NH₄)₃PO₄ + 3Pb(NO₃)₄  →  Pb₃(PO₄)₄ + 12NH₄NO₃

Learn more:

Balanced equation brainly.com/question/11102790

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4 0
3 years ago
A chemist measures the solubility of lead(ii) bromide in water to be 2. 96 g/l. calculate the ksp value for the solid. the ksp v
Julli [10]

The solubility product, ksp of PbBr₂ is 2.102 × 10⁻⁶

<h3>What is solubility?</h3>

The solubility of a solute is defined as the maximum amount of that solute that can be dissolved in a known quantity of solvent at a given temperature.

<h3>What is a solubility product? </h3>

Some salts are sparingly soluble in a solvent. For them, we calculate the solubility product.

It is an equilibrium constant that defines the relationship between a solid and its respective ions in an aqueous solution in equilibrium.

The greater the solubility product, the greater the solubility and vice versa.

Here, the solubility of PbBr₂ = 2.96 g/l

Molar solubility of  PbBr₂ = \frac{2.96}{molar mass of PbBr_2} = 2.96/367 = 8.07 × 10⁻³

At equilibrium,

PbBr_2\rightarrow Pb^{2+} + 2Br^-

1 mole of PbBr2 dissociates into 1 mole of Pb²⁺ ions and 2 moles of Br⁻

Let the molar concentration of Pb²⁺ be x, then the molar concentration of Br⁻ is 2x

Ksp = x.(2x)²

       = 4x³

Substitute, x = 8.07 × 10⁻³

Ksp = 4 (8.07 × 10⁻³)³

      = 2.102 × 10⁻⁶

Thus, The ksp of PbBr₂ is 2.102 × 10⁻⁶

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