Answer:
T°fussion of solution is -18°C
Explanation:
We have to involve two colligative properties to solve this. Let's imagine that the solute is non electrolytic, so i = 1
First of all, we apply boiling point elevation
ΔT = Kb . m . i
ΔT = Boiling T° of solution - Boiling T° of pure solvent
Kb = ebuliloscopic constant
105°C - 100° = 0.512 °C kg/mol . m . 1
5°C / 0.512 °C mol/kg = m
9.7 mol/kg = m
Now that we have the molality we can apply, the Freezing point depression.
ΔT = Kf . m . i
Kf = cryoscopic constant
0° - (T°fussion of solution) = 1.86 °C/m . 9.76 m . 1
- (1.86°C /m . 9.7 m) = T°fussion of solution
- 18°C = T°fussion of solution
Answer: Most methods for making new elements involve a cyclotron, which speeds up atoms to high velocities before they smash into other atoms—these atoms are usually of different elements. This causes the nuclei to combine, creating new heavier elements.
Explanation: How are superheavy elements made?
Explanation:
<h3>PLA is a polyester produced by fermentation under controlled conditions of a carbohydrate source like corn starch or sugarcane. ... The starch is then mixed with acid or enzymes and heated. This process “breaks” starch into dextrose (D-glucose), or corn sugar.</h3>
<h3>PLA is a polymer made from high levels of polylactic acid molecules. </h3><h3>For PLA to biodegrade, you must break up the polymer by adding </h3><h3>water to it (a process known as hydrolyzing). Heat and moisture are required for hydrolyzing to occur.</h3>
<h3>PLA consists of renewable raw materials and is biodegradable in industrial composting plants. </h3><h3>However, due to the lack of infrastructure, it is difficult to </h3><h3>compost PLA industrially or to</h3><h3> recycle it.</h3>
Answer:
isotopes
Atoms with the same number of protons but different numbers of neutrons are called isotopes. Because the number of neutrons can vary for a given element, the mass numbers of different atoms of an element may also vary. For example, some helium atoms have three neutrons instead of two (these are called isotopes and are discussed in detail later on)
Explanation:
