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Harrizon [31]
3 years ago
14

Where can I download high school textbooks online?​

Physics
1 answer:
MArishka [77]3 years ago
6 0

probrably at the schools website but i dont know what school you go to so i would need more info

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If it takes 100 N to move a box 5 meters, what is the work done on the box?
inysia [295]

Answer:

Explanation:

Work=force×distance

W=F×S

   =100 N × 5 m

   = 500 Nm

W = 500J

7 0
3 years ago
The mass of an electron is 9.11 x 10-31 kg. If you want to increase the speed of the
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5 0
3 years ago
Particles q1, 92, and q3 are in a straight line.
NNADVOKAT [17]

The net force on q₃ will be 17.51 N. The net force is the algebraic sum of the two forces on the pleading q₃

<h3 /><h3>What is Columb's law?</h3>

The force of attraction between two charges, according to Coulomb's law, is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

The force,by the charge q₁ on the q₃;

\rm F_{31}} = \frac{Kq_1q_3}{r^2} \\\\ \rm F_{31}}  = \frac{9 \times 10^9 \times -28.1 \times 10^{-6}\times \times -47.9 \times 10^{-6}}{(0.600)^2} \\\\ F_{31}} =33.64 \ N

The force,by the charge q₂ on the q₃;

\rm F_{32}} = \frac{Kq_2q_3}{r^2} \\\\ \rm F_{32}}  = \frac{9 \times 10^9 \times 25.5 \times 10^{-6}\times \times -74.9\times 10^{-6}}{(0.300)^2} \\\\ F_{32}} =-19.09  \ N

The net force is the sum of the two forces;

\rm F_{net}=F_{32}+F_{31}\\\\\ \rm F_{net}=36.6-19.9 \\\\ \rm F_{net}=17.51 \ N

Hence, the net force on q₃ will be 17.51 N.

To learn more about Columb's law, refer to the link;

brainly.com/question/1616890

#SPJ1

8 0
2 years ago
Fine grains of beach sand are assumed to be spheres of radius 49.8 µm. these grains are made of silicon dioxide which has a dens
PIT_PIT [208]

Answer:1.3\times10^{-9}kg

Volume of each grain of sand:

V=\frac{4}{3}\pi r^3

radius of the spherical grain is given,r=49.8\mu m=49.8\times10^{-6} m

\Rightarrow V=\frac{4}{3}\times3.14\times(49.8\times10^{-6})^3m^3=5.17\times10^{-13}m^3

The grains are made up of silicon dioxide.

The density is equal to D=2600 kg/m^3

Then, the mass of each grain is given by:

Mass=Density (D)\times Volume(V)\\ \Rightarrow M=2600 kg/m^3\times5.17\times10^{-13}m^3 =1.3\times10^{-9}kg


6 0
3 years ago
A bullet with a mass ????=12.5 g and speed ????=86.4 m/s is fired into a wooden block with ????=113 g which is initially at rest
skad [1K]

Answer:

a) 8.61 m/s, b) 5.73 m

Explanation:

a) During the collision, momentum is conserved.

mv = (m + M) V

(12.5 g) (86.4 m/s) = (12.5 g + 113 g) V

V = 8.61 m/s

b) After the collision, energy is conserved.

Kinetic energy = Work done by friction

1/2 (m + M) V² = F d

1/2 (m + M) V² = N μk d

1/2 (m + M) V² = (m + M) g μk d

1/2 V² = g μk d

d = V² / (2g μk)

d = (8.61 m/s)² / (2 × 9.8 m/s² × 0.659)

d = 5.73 m

Notice we used the kinetic coefficient of friction.  That's the friction when an object is moving.  The static coefficient of friction is the friction on a stationary object.  Since the bullet/block combination is sliding across the surface, we use the kinetic coefficient.

4 0
3 years ago
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