Question

A fully loaded cart with a mass of 2200 kg starts from the top of a 12-meter hill on a roller coaster.

Answer 1

Answer:

A. potential energy is 258720 Joule

Explanation:

A.Gravitational potential energy is: PE = m × g × h

velocity =  15.33 m/s when the car reaches the bottom of the hill.

where, m = mass

            g = acceleration due to gravity

            h = height from the bottom of hill.

The potential energy is : m×g×h

                                     =(2200×9.8×12)

                                     =258720 Joule

B. at the bottom of the hill, the potential energy is converted into kinetic energy so PE at top = KE at bottom

                    kinetic energy= $\frac{1}{2}$($m*v^{2}$)

where v = velocity

          m= mass

therefore,               v=$\sqrt\frac{2*K.E}{m} {}$

                         or,  v=$\sqrt{\frac{2*258720}{2200} }$

                         or,   v=15.33 m/s