I need help with this physics question

An asteroid, whose mass is 3.6 × 10-4 times the mass of Earth, revolves in a circular orbit around the Sun at a distance that is

frosja888 [35]

Answer:

a) 2.02 years

b) 8.1 x 10⁻⁸.

Explanation:

Time period of a rotating body T² is proportional to radius of orbit R³ So

T₁² / T₂² = R₁³ /R₂³ ( T₁ and R₁ is time period and radius of orbit of the earth .)

1² / T₂² =( 1/1.6)³

T₂ = 2.02 years.

Kinetic energy of an orbiting body = 1/2 m v₀² ( v₀ is orbital speed)

= 1/2 m x 2 g R = m x G m/R² X R= m² x G /R

Kinetic energy of asteroid K₁ / kinetic energy of earth K₂ =

(mass of asteroid/mass of earth)² x( radius of earth / radius of asteroid)

=( 3.6 x 10⁻⁴)² x 1/1.6 = 8.1 x 10⁻⁸ .

7 0

3 years ago

Will Give Brainlist Check pic for question

Harrizon [31]

Ohms law = v= Ir

V= 0.02 x 4000 = 80v

5 0

3 years ago

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If a proton and an electron are released when they are 6.50×10⁻¹⁰ m apart (typical atomic distances), find the initial accelerat

Cerrena [4.2K]

Answer:

(a) Acceleration of electron= 5.993×10²⁰ m/s²

(b) Acceleration of proton= 3.264×10¹⁷ m/s²

Explanation:

Given Data

distance r= 6.50×10⁻¹⁰ m

Mass of electron Me=9.109×10⁻³¹ kg

Mass of proton Mp=1.673×10⁻²⁷ kg

Charge of electron qe= -e = -1.602×10⁻¹⁹C

Charge of electron qp= e = 1.602×10⁻¹⁹C

To find

(a) Acceleration of electron

(b) Acceleration of proton

Solution

Since the charges are opposite the Coulomb Force is attractive

So

$F=\frac{1}{4(\pi)Eo }\frac{|qp*qe|}{r^{2} }\\ F=(8.988*10^{9}Nm^{2}/C^{2})*\frac{(1.602*10^{-19})^{2} }{(6.50*10^{-10} )^{2} } \\F=5.46*10^{-10}N$

From Newtons Second Law of motion

F=ma

a=F/m

For (a) Acceleration of electron

$a=F/Me\\a=(5.46*10^{-10} )/9.109*10^{-31}\\ a=5.993*10^{20}m/s^{2}$

For(b) Acceleration of proton

$a=F/Mp\\a=(5.46*10^{-10} )/1.673*10^{-27} \\a=3.264*10^{17}m/s^{2}$

3 0

3 years ago

There are four forces acting on a car. The forces are:

Elenna [48]

Answer:

| Fn | = 258 N

Explanation:

Net Force

The net force vector is the sum of all the force vectors applied to a body.

There are four forces applied to a car:

325N to the north

175N to the south

465N to the east

255N to the west

To simplify the calculations, we find the net force by each axis separately, considering forces to the right and upward as positive.

Fx = 465 N - 255 N = 210 N

Fy = 325 N - 175 N = 150 N

The magnitude of the net force is:

$|Fn|=\sqrt{210^2+150^2}$

$|Fn|=\sqrt{44100+22500}$

$|Fn|=\sqrt{66600}$

| Fn | = 258 N

4 0

3 years ago

Why screw drivers with long arm are better in use?

Molodets [167]

Answer:

Explanation:

Long screwdrivers are easier to turn because the grip is in the palm of the hand, thus allowing all fingers to contribute. A shorter screwdriver is turned with the thumb and first two or three fingers, providing much less torque.

7 0

3 years ago

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