Answer:
the time comes eventually.
Explanation:
ur body just be giving up
To solve this problem we will apply the expression of charge per unit of time in a capacitor with a given resistance. Mathematically said expression is given as
Here,
q = Charge
t = Time
R = Resistance
C = Capacitance
When the charge reach its half value it has passed 10ms, then the equation is,
We know that RC is equal to the time constant, then
Therefore the time constant for the process is about 14ms
Answer:
Capacitive reactance of the capacitor is 68 ohms
Explanation:
It is given that,
Capacitance,
Frequency,
Capacitive reactance is given by :
or
So, the capacitive reactance of the capacitor is 68 ohms. Hence, this is the required solution.
Answer:
a) J = F t = 40 * .05 = 2 N-s
b) J = 2 N-s momentum changed by 2 N-s
c) Initial momentum appears to be zero
J = change in momentum = m v2 - m v1 = m v2 = 2 N-s
v2 = J / m = 2 / .057 = 35 m/s
d) if the impulse time was increased and the average force remained the same then the change in momentum would increase with a corresponding increase in velocity attained - note the increase in v2 in part c)