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Anna007 [38]
3 years ago
5

If a body has 60N weight what will be its mass on moon

Physics
2 answers:
zvonat [6]3 years ago
8 0
If the object weighs 60N on Earth, then its mass is 6.12 kilograms.

If it weighs 60N on the moon, then its mass is 36.97 kilograms.

Whatever its mass is in one place, it has the same mass in any other place. Mass doesn't depend on location, but weight does.
tatyana61 [14]3 years ago
5 0
W=mg
weight = massx gravitational force
60=9.8m
solve for m
by dividing 60 by 9.8
answer is 
6.12kg
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States that there is an exchange of materials when two objects come into contact with each other
pishuonlain [190]

"Edmond Locard" states that there is an exchange of materials when two objects come into contact with each other.

<u>Explanation:</u>

A French criminologist who was popular as the "Sherlock Holmes of France," the pioneer in forensic science named as Dr. Edmond Locard. He articulated forensic science's fundamental principle "Each touch leaves a trace." This became known as Locard's philosophy of exchange. A Locard hypothesized that each and every time you touch another person, place or object, the result would be an exchange of materials. Burglars, for instance, will leave evidence of their existence behind and take traces with them too.

3 0
2 years ago
Two piano strings produce beats. Frequencies of the strings are 1560 Hz. and 1563 Hz. Choose the correct frequency of the beats.
kakasveta [241]

Beat frequency is given by the difference of two frequencies played together

f_{beat} = |f_1 - f_2|

given that

f_1 = 1560 Hz

f_2 = 1563 Hz

Now

f_{beat} = |1560- 1563| Hz

f_{beat} = 3 Hz

3 0
3 years ago
Read 2 more answers
Given one mole of diamond vs one mole of graphite,
grandymaker [24]

Answer:

The pressure is P= -  6.39*10^8Pa

The temperature is T =1218.63 K

Explanation:

Generally Gibbs free energy is mathematically represented as

                   G = E + PV -TS

   Where  E is the enthalpy

               PV is the pressure volume energy (i.e PV energy)

                S  is the entropy

                T is the temperature

For stability to occur the Gibbs free energy must be equal to zero

Considering Diamond

  So at temperature of  T = 300 K

         E + PV - TS = 0

making P the subject

          P = \frac{TS-E}{V}

Now substituting 300 K for T , 2900 J  for E ,

                              3.42cm^3 = \frac{3.42}{1*10^6} = 3.42*10^{-6}m^3 for V and 2.38 J/K for S

     P = \frac{(300 * 2.38)- 2900}{3.42*10^{-6}}

         P= -  6.39*10^8Pa

The negative sign signifies the direction of the pressure

Given that  P = 1*0^5Pa

making T the subject

            T = \frac{PV+E}{S}

Substituting into the equation

            T = \frac{1*10^5 * 3.42 *10^{-6}+2900}{2.38}

                T =1218.63 K

             

         

7 0
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