Question

A generator has a square coil consisting of 269 turns. The coil rotates at 113 rad/s in a 0.222-T magnetic field. The peak output of the generator is 79.2 V. What is the length of one side of the coil?

Answer 1

Answer:

Explanation:

number of turns, n = 269

angular velocity, ω = 113 rad/s

magnetic field, B = 0.222 T

Voltage, V = 79.2 V

Let the area of the coil is A and the side of the square is s.

The maximum emf generated by the coil is

V = n x B x A x ω

79.2 = 269 x 0.222 x A x 113

A = 0.01174 m²

so, s x s = 0.01174

s = 0.108 m

Thus, the side of the square coil is 0.108 m.

Answer 2

Answer:

length of one side of the coil is 0.1083 m

Explanation:

given data

no of turn = 269

coil rotates = 113 rad/s

magnetic field = 0.222-T

peak output = 79.2 V

solution

we will apply here formula for maximum emf induced in a coil that is

εo = N × A × B × ω    ........................1

and here Area A = l²

so

l = $\sqrt{A}$

put here value of A from equation 1

I = $\sqrt{\frac{\epsilon _o}{N\times B\times \omega} }$  

put here value and we will get

l =  $\sqrt{\frac{79.2}{269\times 0.222\times 113}}$

l = 0.1083 m