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Cloud [144]
2 years ago
9

A car’s tire rotates 5.25 times in 3 seconds. What is the tangential velocity of the tire?

Physics
1 answer:
Lena [83]2 years ago
4 0

The tangential velocity of the car's tire is the product of the angular velocity and radius of the car's tire which is 11(r) m/s.

<h3>Angular velocity of the tire</h3>

The angular velocity of the tire is the rate of change of angular displacement of the tire with time.

The magnitude of the angular velocity of the tire is calculated as follows;

ω = 2πN

where;

  • N is the number of revolutions per second

ω = 2π x (5.25 / 3)

ω =  11 rad/s

<h3>Tangential velocity of the tire</h3>

The tangential velocity of the car's tire is the product of the angular velocity and radius of the car's tire.

The magnitude of the tangential velocity is caculated as follows;

v = ωr

where;

  • r is the radius of the car's tire

v = 11r m/s

Learn more about tangential velocity here: brainly.com/question/25780931

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Answer:

2.4 m/s

Explanation:

Given:

Velocity of the object moving north = 2.1 m/s

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Since the directions of velocity of object and river are perpendicular to each other, the magnitude of the resultant velocity is obtained using Pythagoras Theorem.

The velocities are the legs of the right angled triangle and the resultant velocity is the hypotenuse.

The magnitude of the resultant velocity (R) is given as:

R^2=2.1^2+1.2^2\\\\R^2=4.41+1.44\\\\R=\sqrt{5.85}\\\\R=2.4\ m/s

Therefore, the resultant velocity has a magnitude of 2.4 m/s.

8 0
3 years ago
An investigator places a sample 1.0 cm from a wire carrying a large current; the strength of the magnetic field has a particular
AURORKA [14]

Answer:

she must increase the current by factor of 7

Explanation:

The magnetic field produced by a steady current flowing in a very long straight wire encircles the wire.In order to solve the question, we use this formula,

B= μo I/(2πr)

where,

'μo'  represents permeability of free space i.e 4π*10-7 N/A2

B=magnetic field

I= current

r=radius

->When r= 1cm=> 0.01m

B1 = μo I_{1/(2π x 0.01)

->when r=7cm =>0.07m

B2 = μo I_{2}/(2π x 0.07)

Now equating both of the magnetic fields, we have

B1= B2

μo I_{1/(2π x 0.01)= μo I_{2}/(2π x 0.07)

I_{1/  I_{2}= 0.01/0.07

I_{1/  I_{2}= 1/ 7

Therefore, she must increase the current by factor of 7

5 0
3 years ago
A pendulum is released from rest at point A. If the horizontal line represents the reference point, the pendulum has energy at p
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Only kinetic

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A hayride wagon is going down a spooky country road at 15 m/s when a Scarecrow appears in the roadway. The man at the wheel of t
nexus9112 [7]

Answer:

d = 68.18 m

Explanation:

Given that,

Initial velocity, u = 15 m/s

Finally it comes to stop, v = 0

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Time, t = 2.5 s

We need to find the distance covered by the hayride before coming to a stop. Let d is the distance covered. Using third equation of motion to find it :

v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{-(15)^2}{2\times -1.65}\\\\d=68.18\ m

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