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Korolek [52]
3 years ago
9

Which of these events is an example of the Doppler shift?

Physics
2 answers:
garik1379 [7]3 years ago
5 0
The intensity of an electromagnetic wave increases with the field strength.
Rina8888 [55]3 years ago
4 0
<h3><u>Answer;</u></h3>

The intensity of an electromagnetic wave increases with the field strength.

<h3><u>Explanation;</u></h3>
  • <em><u>Doppler shift also Doppler effect occurs when the source of a wave form sends out waves at a regular rate or frequency, but there is a constant relative motion between the source and the observe, thus causing a change in frequency.</u></em>
  • Electromagnetic waves are waves that do not require a material medium for transmission. Energy in electromagnetic waves is transferred through vibrations of electric and magnetic fields.
  • The strength of electric and magnetic field increases the intensity of an electromagnetic wave, which is an example of Doppler shift.
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A man is standing on the shore of a beach, up to his knees in water. Every second two waves hit him. What is the frequency of th
laila [671]

Answer:

f = 2 Hz

Explanation:

The frequency of a wave is defined as the no. of waves passing per unit of time. Therefore, the frequency of a wave can be calculated by the following formula:

f = \frac{n}{t}

where,

f = frequency of the wave = ?

t = time passed = 1 s

n = no. of waves passing in time t = 2

Therefore,

f = \frac{2}{1\ s}

<u>f = 2 Hz</u>

3 0
3 years ago
Calculate the momentum of a 10kg bowling ball rolling at 2 m/s.
Helen [10]

Answer:

20 kg. m/s

Explanation:

p = mv

m = 10 kg

v = 2 m/s

p = 10 × 2

p = 20 kg m/s

5 0
3 years ago
True Or False;
tino4ka555 [31]
False: because atoms are base on the elements on the periodic table.
3 0
3 years ago
A block with mass m1 = 4.50 kg and a ball with mass m2 = 7.70 kg are connected by a light string that passes over a frictionless
Allisa [31]
1.6a =  \frac{g(m_2 + m_3 - \mu km_1)}{m_1 + m_2 + m_3}  \\  \\ 1.6a(m_1 + m_2 + m_3) = g(m_2 + m_3 - \mu km_1) \\  \\ (1.6a + \mu kg)m_1 + (1.6a - g)m_2 = (g - 1.6a)m_3 \\  \\ m_3 =  \frac{1.6a +\mu kg}{g - 1.6a} m_1 - m_2 \\  \\ m_3 = 22.57 kg
4 0
3 years ago
The heat capacity of object B is twice that of object A. Initially A is at 300 K and B at 450 K. They are placed in thermal cont
ivann1987 [24]

Answer:

The final temperature of both objects is 400 K

Explanation:

The quantity of heat transferred per unit mass is given by;

Q = cΔT

where;

c is the specific heat capacity

ΔT is the change in temperature

The heat transferred by the  object A per unit mass is given by;

Q(A) = caΔT

where;

ca is the specific heat capacity of object A

The heat transferred by the  object B per unit mass is given by;

Q(B) = cbΔT

where;

cb is the specific heat capacity of object B

The heat lost by object B is equal to heat gained by object A

Q(A) = -Q(B)

But heat capacity of object B is twice that of object A

The final temperature of the two objects is given by

T_2 = \frac{C_aT_a + C_bT_b}{C_a + C_b}

But heat capacity of object B is twice that of object A

T_2 = \frac{C_aT_a + C_bT_b}{C_a + C_b} \\\\T_2 = \frac{C_aT_a + 2C_aT_b}{C_a + 2C_a}\\\\T_2 = \frac{c_a(T_a + 2T_b)}{3C_a} \\\\T_2 = \frac{T_a + 2T_b}{3}\\\\T_2 = \frac{300 + (2*450)}{3}\\\\T_2 = 400 \ K

Therefore, the final temperature of both objects is 400 K.

4 0
3 years ago
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