Which of these events is an example of the Doppler shift?

Physics

2 answers:

garik1379 [7]3 years ago

5 0

The intensity of an electromagnetic wave increases with the field strength.

Rina8888 [55]3 years ago

4 0

<h3><u>Answer;</u></h3>

The intensity of an electromagnetic wave increases with the field strength.

<h3><u>Explanation;</u></h3>

<em><u>Doppler shift also Doppler effect occurs when the source of a wave form sends out waves at a regular rate or frequency, but there is a constant relative motion between the source and the observe, thus causing a change in frequency.</u></em>
Electromagnetic waves are waves that do not require a material medium for transmission. Energy in electromagnetic waves is transferred through vibrations of electric and magnetic fields.
The strength of electric and magnetic field increases the intensity of an electromagnetic wave, which is an example of Doppler shift.

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Answer:

a) $\Delta{t} = 5.39s$

b) the motorcycle travels 155 m

Explanation:

Let $t_2-t_1 = \Delta{t}$ , then consider the equation of motion for the motorcycle (accelerated) and for the car (non accelerated):

$v_{m2}=v_0+a\Delta{t}\\x+d=(\frac{v_0+v_{m2}}{2} )\Delta{t}\\v_c = v_0 = \frac{x}{\Delta{t}}$

where:

$v_{m2}$ is the speed of the motorcycle at time 2

$v_{c}$ is the velocity of the car (constant)

$v_{0}$ is the velocity of the car and the motorcycle at time 1

d is the distance between the car and the motorcycle at time 1

x is the distance traveled by the car between time 1 and time 2

Solving the system of equations:

$\left[\begin{array}{cc}car&motorcycle\\x=v_0\Delta{t}&x+d=(\frac{v_0+v_{m2}}{2}}) \Delta{t}\end{array}\right]$

$v_0\Delta{t}=\frac{v_0+v_{m2}}{2}\Delta{t}-d \\\frac{v_0+v_{m2}}{2}\Delta{t}-v_0\Delta{t}=d\\(v_0+v_{m2})\Delta{t}-2v_0\Delta{t}=2d\\(v_0+v_0+a\Delta{t})\Delta{t}-2v_0\Delta{t}=2d\\(2v_0+a\Delta{t})\Delta{t}-2v_0\Delta{t}=2d\\a\Delta{t}^2=2d\\\Delta{t}=\sqrt{\frac{2d}{a}}=\sqrt{\frac{2*58}{4}}=\sqrt{29}=5.385s$