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Lady_Fox [76]
3 years ago
11

Uplift occurs at a rate of 0.1 m per 1,000 years. How much will the uplift change over 100,000 years? 10 m 100 m 1,000 m 10,000

m
Chemistry
2 answers:
aliya0001 [1]3 years ago
5 0
<h3>Answer:</h3>

= 10 m

<h3>Explanation:</h3>

We are given;

Uplift rate is 0.1 m per 1,000 years

We can get the time taken an uplift change of 1 m

= 1,000 years ÷ 0.1 m

= 10,000 years per 1 m

uplift change of 1 m takes 10,000 years

Therefore, for 100,000 years the uplift change will be;

 = 100,000 years ÷ 10,000 years/m

 = 10 m

Therefore, the uplift will change in 10 m within 100,000 years

sabrina mcgowan3 years ago
0 0

Uplift occurs at a rate of 0.1 m per 1,000 years.

How much will the uplift change over 1,000,000 years?


0.1 m

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An aqueous solution in a 55 gallon (208 l drum), characterized by minimal buffering capacity, received 4kg of phenol and 1.5 kg of sodium phenate. What is the ph of the solution. The pka of phenol = 9.98. Mw of phenol and sodium phenate are 94 g/mol and 116 g/mol, respectively.


Volume of solution = 55 gallons = 208.2 L [ 1 gallon = 3.78 L]

moles of phenol = mass / molar mass = 4000 g / 94 = 42.55 moles

moles of sodium phenate = mass / molar mass = 1500 / 116 = 12.93 moles

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We know that the pH of buffer is calculated using Hendersen Hassalbalch's equation

pH = pKa + log [salt] / [acid]

volume is same for both the sodium phenate and phenol has we can directly take the moles of each in the formula

pH = 9.98 + log [12.93 / 42.55] = 9.46



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