Heat required to raise the temperature = 159.505 J
<h3>Further explanation</h3>
Given
c = specific heat of Beryllium = 1.825 J/g C
m = mass = 2.3 g
Δt = Temperature difference : 60 - 22 = 38 °C
Required
Heat required
Solution
Heat can be formulated
Q = m.c.Δt
Input the value :
Q = 2.3 x 1.825 x 38
Q = 159.505 J
Answer:
24.24 L
Explanation:
Boyle’s law, also called Mariotte’s law, a relation concerning the compression and expansion of a gas at constant temperature.
This empirical relation, formulated by the physicist Robert Boyle in 1662, states that the pressure (p) of a given quantity of gas varies inversely with its volume (v) at constant temperature; i.e., in equation form, pv = k, a constant.
Real gases obey Boyle’s law at sufficiently low pressures, although the product pv generally decreases slightly at higher pressures, where the gas begins to depart from ideal behaviour.
As, PV = k
P₁ V₁ = P₂ V₂
Given P₁ = 101 KPa
V₁ = 6 L
P₂ = 25 kPa
So, V₂ = P₁ V₁ /P₂ = 101 *6/25 = 24.24 L
The answer is 4. It can hold 4 sublevels as s.p,d,f and it holds 32 electrons
Answer: (Structure attached).
Explanation:
This type of reaction is an aromatic electrophilic substitution. The overall reaction is the replacement of a proton (H +) with an electrophile (E +) in the aromatic ring.
The aromatic ring in p-fluoroanisole has two sustituents, an <u>halogen</u> and a <u>methoxy group</u>, which are <em>ortho-para</em> directing substituents.
Aryl sulfonic acids are easily synthesized by an electrophilic substitution reaction aromatic using <u>sulfur trioxide as an electrophile</u> (very reactive).
The reaction occurs in three steps:
- The attack on the electrophile forms the sigma complex.
- The loss of a proton regenerates an aromatic ring.
- The sulfonate group can be protonated in the presence of a strong acid (H₂SO₄).
Normally, a mixture of <em>ortho-para</em> substituted products would be obtained. However, since both <em>para</em> positions are occupied, only the <em>ortho </em>substituted product is obtained here.
X moles of hot water vapor(H2O) * 1 mol Fe3O4 / 4 mol H2O * 233.55g Fe3O4 / 1 mol = 275 g
Solve the equation
x = 4.71 mol of hot water vapor (steam)
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