(a) before the submarines pass each other, sub b quickly turns around and speeds up to 12. 4 m/s. What is the change in frequenc
2 answers:
The frequency is the number of waves that travel through a particular place in one unit of time. The change in frequency noticed by observers on sub b is 2.66 Hz.
<h3>What is the frequency?</h3>The frequency is the number of waves that travel through a particular place in one unit of time. It may also be described as the number of cycles or vibrations experienced by a body in periodic motion in one unit of time.
Given that the new speed of the sub B is 12.4 m//sec, while the frequency of the submarine is 1416.44 Hz. The frequency of the sonar wave of submarine A is 1400 Hz. Also, the speed of sound in water, V is 1533 m/sec, and the speed of submarine A is 8.4 m/s.
Now, the frequency of the sub B after the speed is increased will be equal to,
Further, the change in frequency noticed by observers on sub b,
Hence, the change in frequency noticed by observers on sub b is 2.66 Hz.
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Answer:
(a) Electric field at 0.250 m is zero.
(b) Electric field at 2.90 m is zero.
(c) Electric field at 3.10 m is - 5.15 x 10³ V/m.
(d) Electric field at 8.00 m is - 0.77 x 10³ V/m.
Explanation:
Let Q and R are the charge and radius of the solid metal sphere. The solid metal sphere behave as conductor, so total charge Q is on the surface of the sphere.
Electric field inside and outside the metal sphere is :
E = 0 for r ≤ R ( inside )
= for r > R ( outside )
Here K is electric constant and r is the distance from the center of the metal sphere.
(a) Electric field at 0.250 m is zero as r < R i.e. 0.250 m < 3 m from the above equation.
(b) Electric field at 2.90 m is zero as r < R i.e. 2.90 m < 3 m from the above equation.
(c) Electric field at 3.10 m is given by the relation as r > R :
E =
Substitute 9 x 10⁹ N m²/C² for K, -5.50 μC for Q and 3.10 m for r in the above equation.
E = -
E = - 5.15 x 10³ V/m
(d) Electric field at 8.00 m is given by the relation as r > R :
E =
Substitute 9 x 10⁹ N m²/C² for K, -5.50 μC for Q and 8.00 m for r in the above equation.
E = -
E = - 0.77 x 10³ V/m