Answer:
Explanation:
The collision is elastic as no frictional force exists .
Both momentum and energy will be conserved.
We shall apply velocity formula applicable in respect of elastic collision
m₁ and m₂ be mass of red and green T shirt player , u₁ and u₂ be their initial velocity , v₁ and v₂ be their final velocity
v₂ = (m₂-m₁)u₂ / ( m₁+m₂) + 2 m₁u₁ / ( m₁+m₂)
Given m₁ = 40 kg , m₂ = 60 kg , v₂ = 2 m /s , u₁ = ? , u₂ = 0
Put the values in the equation
2 = 0 + 2 x 40 x u₁ / ( 40 + 60 )
u₁ = 2.5 m /s .
Initial speed of red T- shirt .
Answer:
Height, h = 10.20 meters
Explanation:
It is given that,
Mass of the object, m = 3 kg
Energy of object, E = 300 J
Let it will moved to a height of h. The energy possessed by it is called gravitational potential energy. It is given by :
h = 10.20 meters
So, the object will move to height of 10.20 meters. Hence, this is the required solution.
Answer:
His first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force. ... The amount of the change in velocity is determined by Newton's second law of motion.
Answer:
During an experiment, a student moves a cell from pure water to salted water. ... It will release water and shrivel. It will release water and burst.
Answer:
F = 19.1 N
Explanation:
To find the force exerted by the string on the block you use the following formula:
(1)
k: spring constant = 95.5 N/m
x: displacement of the block from its equilibrium position = 0.200 m
you replace the values of k and x in the equation (1):
Hence, the force exterted on the block is 19.1 N