How many times as fast as a propeller plane at 266 mph is a jet at 625 mph?

ellie brought 60 cookies to class today. 30% of them have mint filing. how many cookies have the mint filling

Elan Coil [88]

So simple.

18.

If you need help to find why, here's a link

http://www.geteasysolution.com/what-is-30-percent-of-60

5 0

3 years ago

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What is the radius?<br><br> PLEASE HELP

KiRa [710]

I hope this helps you

7 0

3 years ago

Which equation has 1 solution?

ser-zykov [4K]

Well, we can eliminate the first 2 options as an absolute value of either a positive or negative number will yield a positive number. The absolute value of 0 is 0. This there is only 1 solution for this, and that is 0. The solution would be C.

It can't be D, because in both cases the absolute value of -1 and 1 will be 1 and thus there are 2 solutions, -1 and 1.

5 0

3 years ago

A random draw is being designed for 210 participants. A single winner is to be chosen, and all the participants must have an equ

Over [174]

Answer: The correct number of balls is (b) 4.

Step-by-step explanation: Given that a single winner is to be chosen in a random draw designed for 210 participants. Also, there is an equal probability of winning for each participant.

We are using 10 balls, numbered through 0 to 9. We are to find the number of balls which needs to be picked up, regardless of order, so that each of the 210 participants can be assigned a unique set of numbers.

Let 'r' represents the number of balls to be picked up.

Since we are choosing from 10 balls, so we must have

$^{10}C_r=210.$

The value of 'r' can be any one of 0, 1, 2, . . , 10.

Now,

if r = 1, then

$^{10}C_1=\dfrac{10!}{1!(10-1)!}=\dfrac{10!}{1!9!}=\dfrac{10\times 9!}{1\times 9!}=10$

If r = 2, then

$^{10}C_2=\dfrac{10!}{2!(10-2)!}=\dfrac{10!}{2!8!}=\dfrac{10\times 9\times 8!}{2\times 1\times 8!}=45$

If r = 3, then

$^{10}C_3=\dfrac{10!}{3!(10-3)!}=\dfrac{10!}{3!7!}=\dfrac{10\times 9\times 8\times 7!}{3\times 2\times 1\times 7!}=120$

If r = 4, then

$^{10}C_4=\dfrac{10!}{4!(10-4)!}=\dfrac{10!}{4!6!}=\dfrac{10\times 9\times 8\times\times 7\times 6!}{4\times 3\times 2\times 1\times 6!}=210.$

Therefore, we need to pick 4 balls so that each participant can be assigned a unique set of numbers.

Thus, (b) is the correct option.

4 0

3 years ago

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Evaluate each expression. Name the property used in each step.

IRINA_888 [86]

1. (1 / 5)5 * 14 = 14 because 1/5 multplied by 5 is equal to 1. I believe this is called reciprocals.

2. 6 + 4 (19 - 5) = 6 + 4(19) - 4(5) = 6 + 76 - 20 = 62. This is called the distributive property.

3. 5 (14 - 5) + 6 (3 + 7) = 5(14) - 5(5) + 6(3) + 6(7) = 70 - 25 + 18 + 42 = 105. We also used the distributive property in this question.

4 0

3 years ago