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Ahat [919]
3 years ago
6

How many liters of O2 will form at STP if 22.5 g H2O2 react?

Chemistry
1 answer:
Mumz [18]3 years ago
3 0

Answer: 7.41 L of O2

Explanation:

2H2O2(l) ----> 2H2O(l) + O2(g)

22.5 g H2O2  x __1 mol__ x __1 mol O2__ x __22.4 L__ = 7.41 L of O2

                            34.016 g       2 mol H2O2       1 mol O2

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A typical aspirin tablet contains 5.00 grains of pure aspirin analgesic compound. The rest of the tablet is
Pavel [41]

Answer:

Tablets=193

Explanation:

Hello,

In this case, given that a typical aspirin tablet contains 5.00 grains of pure aspirin, the first step here is to compute the mass of those grans per tablet given that 1.00 g = 15.4 grains:

m=5.00grains*\frac{1.00g}{15.4grains}=0.325g

In such a way, the number of aspirin tablets are computed considering the total mass of aspirin and the mass per tablet:

Tablets=\frac{62.7g}{0.325g}\\ \\Tablets=193

Best regards.

8 0
3 years ago
Mg3N2(s)+6H2O(l)→3Mg(OH)2(s)+2NH3(g) When 36.0 g of H2O react, how many grams of NH3 are produced? When 36.0 g of H2O react, how
Afina-wow [57]

Answer:

11.3 g of NH_{3} are produced from 36.0 g of H_{2}O

Explanation:

1. The balanced chemical equation is the following:

Mg_{3}N_{2}(s)+6H_{2}O(l)=3Mg(OH)_{2}(s)+2NH_{3}(g)

2. Use the molar mass of the H_{2}O, the molar mass of the NH_{3} and the stoichiometry of the balanced chemical reaction to find how many grams of NH_{3} are produced:

Molar mass H_{2}O = 18\frac{g}{mol}

Molar mass NH_{3} = 17\frac{g}{mol}

36.0gH_{2}O*\frac{1molH_{2}O}{18gH_{2}O}*\frac{2molesNH_{3}}{6molesH_{2}O}*\frac{17gNH_{3}}{1molNH_{3}}=11.3gNH_{3}

Therefore 11.3 g of NH_{3} are produced from 36.0 g of H_{2}O

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kakasveta [241]

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Apex

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