Which of the following are NOT steps for balancing chemical equations?

Chemistry

1 answer:

Mama L [17]3 years ago

8 0

Explanation:

In order to balance a chemical equation, it is required that the number of reactant atoms or molecules should equal the number of product atoms or molecules.

For this, we first of all write the chemical formulas and symbols on both reactant and product side. Then we count the number of individual atom on the reactant and product side followed by multiplication or division of according to the count of respective atom.

For example, $N_{2} + 3H_{2} \rightarrow 2NH_{3}$

Here the number of nitrogen atoms on reactant side should be equal to the number of nitrogen atoms on product side. Similarly, the number of hydrogen atoms on reactant side should be equal to the number of hydrogen atoms on product side. Only then this equation will be balanced.

Therefore, we can conclude that out of the given options, the statements which are not true are as follows.

Subtract the total amount of elements from the products.
Add all the elements together.

You might be interested in

4. In a solution, what pulls particles into the solution?

Tanya [424]

The correct answer to your question is B, solvent.
let me know if you have any further questions
:)

3 0

3 years ago

I'm hot right? here's a pic of me

viva [34]

DANNNNNNNNNNNNGGGGGG hella hot, the hottest I seen in this world !!

4 0

2 years ago

Read 2 more answers

Which is a characteristic of a solution1. its particles scatter light2. ita particles are evenly distributed 3. its particles se

FrozenT [24]

A colloid has the particles that have the ability to scatter light called the Tyndall effect named after the scientist named Tyndall. A suspension has large suspended particles that settle out at the bottom of the container. A solution has small particles that are evenly distributed throughout. Hence the answer is choice 2.

8 0

4 years ago

Read 2 more answers

The question is in the picture below

Rus_ich [418]

Answer:

$\Delta\text{H}_1+2\Delta\text{H}_2-\Delta\text{H}_3$

Explanation:

Hess's Law of Constant Heat Summation states that if a chemical equation can be written as the sum of several other chemical equations, the enthalpy change of the first chemical equation is equal to the sum of the enthalpy changes of the other chemical equations. Thus, the reaction that involves the conversion of reactant A to B, for example, has the same enthalpy change even if you convert A to C, before converting it to B. Regardless of how many steps it takes for the reactant to be converted to the product, the enthalpy change of the overall reaction is constant.

With Hess's Law in mind, let's see how A can be converted to 2C +E.

$\bf{\text{A} \rightarrow 2\text{B}}$ (Δ $\text{H}_1$ ) -----(1)

Since we have 2B, multiply the whole of II. by 2:

$\bf{2\text{B} \rightarrow 2\text{C} +2\text{D}}$ (2Δ $\text{H}_2$ ) -----(2)

This step converts all the B intermediates to 2C +2D. This means that the overall reaction at this stage is $\text{A} \rightarrow 2\text{C} +2\text{D}$ .

Reversing III. gives us a negative enthalpy change as such:

$\bf{2\text{D} \rightarrow \text{E}}$ (-Δ $\text{H}_3$ ) -----(3)

This step converts all the D intermediates formed from step (2) to E. This results in the overall equation of $\text{A} \rightarrow 2\text{C} +\text{E}$ , which is also the equation of interest.