Which of the following are NOT steps for balancing chemical equations?
1 answer:
Explanation:
In order to balance a chemical equation, it is required that the number of reactant atoms or molecules should equal the number of product atoms or molecules.
For this, we first of all write the chemical formulas and symbols on both reactant and product side. Then we count the number of individual atom on the reactant and product side followed by multiplication or division of according to the count of respective atom.
For example,
Here the number of nitrogen atoms on reactant side should be equal to the number of nitrogen atoms on product side. Similarly, the number of hydrogen atoms on reactant side should be equal to the number of hydrogen atoms on product side. Only then this equation will be balanced.
Therefore, we can conclude that out of the given options, the statements which are not true are as follows.
- Subtract the total amount of elements from the products.
- Add all the elements together.
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Answer:
The standard enthalpy of formation of NOCl(g) at 25 ºC is 105 kJ/mol
Explanation:
The ∆H (heat of reaction) of the combustion reaction is the heat that accompanies the entire reaction. For its calculation you must make the total sum of all the heats of the products and of the reagents affected by their stoichiometric coefficient (number of molecules of each compound that participates in the reaction) and finally subtract them:
Enthalpy of the reaction= ΔH = ∑Hproducts - ∑Hreactants
In this case, you have: 2 NOCl(g) → 2 NO(g) + Cl₂(g)
So, ΔH=
Knowing:
- ΔH= 75.5 kJ/mol
= 90.25 kJ/mol
= 0 (For the formation of one mole of a pure element the heat of formation is 0, in this caseyou have as a pure compound the chlorine Cl₂)
=?
Replacing:
75.5 kJ/mol=2* 90.25 kJ/mol + 0 -
Solving
-=75.5 kJ/mol - 2*90.25 kJ/mol
-=-105 kJ/mol
=105 kJ/mol
<u><em>The standard enthalpy of formation of NOCl(g) at 25 ºC is 105 kJ/mol</em></u>