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3 years ago

Which of the following are NOT steps for balancing chemical equations?

Chemistry

1 answer:

Mama L [17]3 years ago

8 0

Explanation:

In order to balance a chemical equation, it is required that the number of reactant atoms or molecules should equal the number of product atoms or molecules.

For this, we first of all write the chemical formulas and symbols on both reactant and product side. Then we count the number of individual atom on the reactant and product side followed by multiplication or division of according to the count of respective atom.

For example, $N_{2} + 3H_{2} \rightarrow 2NH_{3}$

Here the number of nitrogen atoms on reactant side should be equal to the number of nitrogen atoms on product side. Similarly, the number of hydrogen atoms on reactant side should be equal to the number of hydrogen atoms on product side. Only then this equation will be balanced.

Therefore, we can conclude that out of the given options, the statements which are not true are as follows.

Subtract the total amount of elements from the products.
Add all the elements together.

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Answer: Frost weathering is a collective term for several mechanical weathering processes induced by stresses created by the freezing of water into ice.

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3 years ago

How do u find ratios of unknown value

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3 years ago

A large balloon is initially filled to a volume of 25.0 L at 353 K and a pressure of 2575 mm Hg. What volume of gas will the bal

bija089 [108]

Answer:

45.0 L is the volume of gas will the balloon contain at 1.35 atm and 253 K.

Explanation:

Using Ideal gas equation for same mole of gas as

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

Given ,

V₁ = 25.0 L

V₂ = ?

P₁ = 2575 mm Hg

Also, P (atm) = P (mm Hg) / 760

P₁ = 2575 / 760 atm = 3.39 atm

P₂ = 1.35 atm

T₁ = 353 K

T₂ = 253 K

Using above equation as:

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

$\frac{{3.39}\times {25.0}}{353}=\frac{{1.35}\times {V_2}}{253}$

$\frac{1.35V_2}{253}=\frac{3.39\times \:25}{353}$

Solving for V₂ , we get:

45.0 L is the volume of gas will the balloon contain at 1.35 atm and 253 K.

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3 years ago

2. What is the molarity of 100 mL of a 3.0% H2O2 (mass/volume) solution? What is the molarity of 100 mL of a 2.25% H2O2 solution

KatRina [158]

The 3% mass/volume H₂O₂ means 3 g of H₂O₂ in 100 ml of water.

Now, Molarity (M) = No. of moles of H₂O₂ / Volume of solution in liter

No. of moles of H₂O₂ = Mass / Molar mass = 3 g / 34 g/mol = 0.088 mol

So, molarity = 0.088 × 1000 ml / 100 ml = 0.88 M

In case of 2.25 % H₂O₂,

No of moles = 2.25 g / 34 g/mol = 0.066 mol

Molarity = 0.066 mol / 0.100 L = 0.66 M.

7 0

3 years ago

What is the percentage error of length measurement of 0.229cm if the correct value is 0.225cm

Mars2501 [29]

Percent error is the difference between the measured and known value, divided by the known value, multiplied by 100%.

So first, we take our measured value, .299 cm, minus our known value, .225 cm.

.299 cm - .225 cm=.004 cm

Next, we divide that by our known value

$\frac{.004}{.225}=.0177777778$

Finally, multiply your answer by 100

.0177777778 x 100= 1.77777778 %

Round to three significant figures, and you're done.

=1.78 % error

5 0

3 years ago

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