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Flauer [41]
3 years ago
4

Determine the cell notation for the redox reaction given below. 3 Cl2(g) + 2 Fe(s) --> 6 Cl-(aq) + 2 Fe3+(aq) ) Fe3+(aq) | Fe

(s) || Cl-(aq) | Cl2(g) | Pt
Cl2(g) | Cl-(aq) | Pt || Fe(s) | Fe3+(aq)

Fe(s) | Fe3+(aq) || Cl2(g) | Cl-(aq) | Pt

Cl-(aq) | Cl2(g) | Pt || Fe3+(aq) | Fe(s)

Fe(s) | Cl2(g) || Fe3+(aq) | Cl-(aq) | Pt
Chemistry
1 answer:
DerKrebs [107]3 years ago
4 0

Answer:

Fe(s) | Fe3+(aq) || Cl2(g) | Cl-(aq) | Pt

Explanation:

For the given reaction -

3 Cl₂(g) + 2 Fe(s)  →  6 Cl⁻(aq) + 2 Fe³⁺(aq)  

The reaction have two halves , where there is oxidation process as well as reduction process .

Oxidation process - the process of increase in the number of oxidation state .

And ,

Reduction process - the process of reduction of the number of oxidation state .  

Hence , from the reaction ,

Oxidation process -

Fe(s) → Fe³⁺(aq)

and ,

Reduction process -

Cl₂(g) → Cl⁻(aq)

<u>Writing the cell notation - </u>

The oxidation half is written first and followed by the reduction process , which is separated by the salt bridge .

hence , the cell notation for the above reaction is -

Fe(s) | Fe³⁺(aq) || Cl₂(g) | Cl⁻(aq) | Pt

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diamong [38]

Answer:

Theoretical yield of C6H10 = 3.2 g.

Explanation:

Defining Theoretical yield as the quantity of product obtained from the complete conversion of the limiting reactant in a chemical reaction. It can be expressed as grams or moles.

Equation of the reaction

C6H11OH --> C6H10 + H2O

Moles of C6H11OH:

Molar mass of C6H110H = (12*6) + (1*12) + 16

= 100 g/mol

Mass of C6H10 = 3.8 g

number of moles = mass/molar mass

=3.8/100

= 0.038 mol.

Using stoichoimetry, 1 moles of C6H110H was dehydrated to form 1 mole of C6H10 and 1 mole of water.

Therefore, 0.038 moles of C6H10 was produced.

Mass of C6H10 = molar mass * number of moles

Molar mass of C6H10 = (12*6) + (1*10)

= 82 g/mol.

Mass = 82 * 0.038

= 3.116 g of C6H10.

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4 0
4 years ago
Question 22
ruslelena [56]

Answer:

O2, oxygen.

Explanation:

Hello.

In this case, for the undergoing chemical reaction, we need to compute the moles of CO2 yielded by 85 g of CH4 (molar mass = 16 g/mol) and by 320 g of O2 (molar mass 32 g/mol) via the following mole-mass relationships:

n_{CO_2}^{by\ CH_4}=85gCH_4*\frac{1molCH_4}{16gCH_4} *\frac{1molCO_2}{1molCH_4} =5.3molCO_2\\\\n_{CO_2}^{by\ O_2}=320gO_2*\frac{1molO_2}{32gO_2} *\frac{1molCO_2}{2molO_2} =5molCO_2

Considering the 1:2:1 among CH4, O2 and CO2. Therefore, since 320 g of O2 yield the smallest amount of CO2 we infer that the limiting reactant is O2.

Best regards.

5 0
3 years ago
Can you Find the quotient of 1/4 of 3
Romashka [77]

Answer: 1/12

1/4 divided by 3/1

KCF:Keep the first fraction, Change the sign to muplication, Flip the second fraction.

1/4* 31

1*1=1

4*3=12

1/12

7 0
4 years ago
Which is an example of the electromagnetic force? A compass needle points north toward Earth’s magnetic pole. An iron nail rolls
Harman [31]

answer:

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Explanation:

because of the earths magnetic field.

4 0
3 years ago
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A spectrophotometer measures the transmittance or the absorbance, or both, of a particular wavelength of light after it has pass
Taya2010 [7]

Answer:

b. The transmittance of the cuvette must be measured in the same place each time.

Explanation:

When using a spectrophotometer, light passes not only through the liquid sample, it also passes through the cuvette. This means that each time a reading is made, you not only measure the transmittance/absorbance of the sample, <u>but of the cuvette as well</u>.

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4 0
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