Answer: The product from the reduction reaction is
CH3-CH2-CH(CH3)-CH2-CH2OH
IUPAC name; 3- Methylpentan-1-ol
Explanation:
Since oxidation is simply the addition of oxygen to a compound and reduction is likewise the addition of hydrogen to a compound.
Therefore, hydrogen is added onto the carbon atom adjacent to oxygen in 3- methyl pentanal
CH3 CH2 CHCH3 CH2 CHO thereby -CHO( aldehyde functional group) are reduced to CH2OH ( Primary alcohol) which gives;
3-methylpenta-1-ol .
The structure of the product is:
CH3-CH2-CH(CH3)-CH2-CH2OH
Answer:
Explanation:
To be accurate, it must be able to make measurements that are close to the actual value.
Hello!
You would expect to observe
2 triplets in the ¹H NMR spectra for o-chlorotoluene.
Multiplicity observed in ¹H NMR spectra when the atom couples with a neighbor ¹H atom. The multiplicity is equal to
N+1 where N is the number of neighbor atoms.
To observe a triplet, you'll need a molecule with 2 neighbor atoms. In o-chlorotoluene (shown in the figure), only protons C and D have 2 neighbor atoms (B and D; A and C, respectively), so you'll expect to see a 2 triplets.
Have a nice day!
Answer: Thus
is a secondary alkanol.
Explanation:
Alkanol are compounds which contains carbons bonded by single bonds and contains hydroxy (-OH) as functional group.
Primary alkanol are those compounds which contain hydroxyl group attached a carbon which is further attached to a single carbon atom. Example:
and 
Secondary alkanol are those compounds which contain hydroxyl group attached to a carbon which is further attached to two more carbon atoms.Example:
Tertiary alkanol are those compounds which contain hydroxyl group attached to a carbon which is further attached to three more carbon atoms. Example: 
Thus
is a secondary alkanol.