Answer:
-1435 kJ
Explanation:
The Gibbs free energy, ΔG is an indication the amount of (useful) work that can be obtained from a chemical reaction involving reacting species and it is negative for spontaneous reaction
ΔG° = ΔH° - TΔS
ΔG = ΔG° + RT㏑Q
ΔG = G (reactants) - G(products)
Given that the combustion reaction of glucose is as follows;
C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O
The above reaction has a ΔG° value of -2870 kJ
Therefore, the free energy for half mole of glucose = -2870 kJ/2 = -1435 kJ
Rivers and streams though that’s not the wording I would use
Answer:
i think it will be c. The acid in solution A is less concentrated than in solution B and is also a stronger acid than that in solution B. im not for sure
Explanation:
Answer: The mass is 980.6g of Gold.
Explanation:
We begin by looking for the number of moles equivalent to 3.0 x 10^24 gold atoms.
Using the Avogadro's number,
6.02 x 10^23 atoms of gold make up 1 mole of gold.
3.0 x 10^24 atoms would make up: 1 / 6.02 x 10^23 x 3.0 x 10^24 = 4.98moles.
Now that we know the number of moles, we can then look for the mass using the formular:
Moles = mass/ molar mass
4.98 = mass / 196.9 (atomic mass of gold)
Making "mass" the subject of formula : mass = 4.98 x 196.9= 980.6g
