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Lubov Fominskaja [6]
2 years ago
15

5.01 moles of magnesium phosphate contain how many atoms of phosphorus?

Chemistry
1 answer:
VMariaS [17]2 years ago
5 0

Answer:

Explanation:

Deal with 1 mole first.

The chemical formula of Magnesium Phosphate is

Mg3(PO4)2

The 2 tells you that there are 2 mols of Phosphorus in the chemical.

1 mol of anything is 6.02 * 10^23 (in this case) atoms.

2 mols of anything is 12.04 * 10^23 atoms

2 moles of anything is 1.204 * 10^24 (the 2 answers are the same. This one is more correct in scientific notation.)

Now we come to the 5.01. Where does that go?

5.01 * Mg3(PO4)2

So multiply 1.204 * 10^24 by 5.01 When you do, you get

7.26 * 10^24 atoms

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Hope it helps

4 0
3 years ago
The essential oil found in cloves, eugenol, can be isolated by steam distillation because it is insoluble in water and has a mea
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We know that:
Molar Mass H2O: 18 g/mol 
<span>Molar Mass of Eugenol: 164 g/mol </span>
<span>Boiling point of H2O: 100 degrees C </span>
<span>Boiling point of Eugenol: 254 degrees C </span>
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<span>Density of Eugenol: 1.05 g/mL </span>

<span>Using formula:
V= [mole fraction x molar mass] / density </span>

<span>mH20: 0.9947 * 18
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          = 17.9046 </span>
<span>morg: 0.0053 * 164  
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<span>V% = Vorg/(Vorg + VH2O) * 100 </span>
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<span>(m eug/mH2O) = (peug*164/pH2O*18) </span>
<span>(m eug/30) = (4*164/760*18) </span>
<span>m eug = about 1.44g and </span>
<span>
volume = mass/density
            = 1.44/1.05
            = about 1.37 mL </span>
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