All categories

3 years ago

True or False. A force is a push or pull exerted on an object.

Chemistry

2 answers:

tangare [24]3 years ago

6 0

Answer:

True.

Explanation:

drek231 [11]3 years ago

4 0

Answer:

TRUE

Explanation:

remember newtons laws of motion. Every action has an equal and opposite reaction. LOL

You might be interested in

The pressure of a sample of helium in a 200. ml. container is 2.0 atm. If the 5 points

just olya [345]

The pressure of the gas = 40 atm

<h3>Further explanation</h3>

Given

200 ml container

P = 2 atm

final volume = 10 ml

Required

Final pressure

Solution

Boyle's Law

At a fixed temperature, the gas volume is inversely proportional to the pressure applied

$\tt \rm p_1V_1=p_2.V_2\\\\\dfrac{p_1}{p_2}=\dfrac{V_2}{V_1}$

Input the value :

P₂ = P₁V₁/V₂

P₂ = 2 x 200 / 10

P₂ = 40 atm

3 0

3 years ago

Oxidation/reduction (redox) reactions like this: 2H2(g) + O2(g) ⇒ 2H2O(l) will occur spontaneously. To make the reaction proceed

igor_vitrenko [27]

The process is called electrolysis.

3 0

3 years ago

Ill give u brainliest and all my points! pls help

dexar [7]

http://www.atnf.csiro.au/outreach/education/senior/cosmicengine/stars_hrdiagram.html. This will give u the answer, just go to link

6 0

3 years ago

Which product of petroleum is normally used as fuel in cars and light vehicles

Elena L [17]

Answer:

mostly gasoline in cars nowadays

8 0

3 years ago

Read 2 more answers

A certain substance X has a normal freezing point of -6.4 C and a molal freezing point depression constant Kf= 3.96 degrees C.kg

Brut [27]

Answer: $1.0\times 10^2g$

Explanation:

Depression in freezing point is given by:

$\Delta T_f=i\times K_f\times m$

$\Delta T_f=T_f^0-T_f=(-6.4-(13.6))^0C=7.2^0C$ = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte like urea)

$K_f$ = freezing point constant = $3.96^0C/m$

m= molality

$\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}}\times \text{weight of solvent in kg}}$

Weight of solvent (X)= 950 g = 0.95 kg

Molar mass of non electrolyte (urea) = 60.06 g/mol

Mass of non electrolyte (urea) added = ?

$7.2=1\times 3.96\times \frac{xg}{60.06 g/mol\times 0.95kg}$

$x=1.0\times 10^2g$

Thus $1.0\times 10^2g$ urea was dissolved.

8 0

3 years ago