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3 years ago

Which of the following factors can be changed for a gas without changing the mass of the gas? Select all that apply.

Chemistry

2 answers:

viva [34]3 years ago

8 0

It is either
volume or pressure

vodomira [7]3 years ago

8 0

Explanation:

Volume is the space occupied by a substance in a container or vessel.

Temperature is the measure of degree of hotness present in a substance or object.

Density is defined as the mass present in per unit volume of a substance. So, more is the mass of a substance more will be its density.

Also, more is the number of particles present in a substance more will be its mass.

Pressure is defined as the push applied on a substance due to which molecules of a gas will come closer to each other.

Therefore, we can conclude that factors which can be changed for a gas without changing the mass of the gas are volume, temperature, and pressure.

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A book is sitting on a desk. The area of contact between the book and the desk is 0.06 m2 of the body's weight is 30 N what is t

tekilochka [14]

Answer:

500N/m²

Explanation:

The Pressure can be calculated using the formula:

P = F/A

Where;

F = force (N)

A = Area (m²)

Based on the information provided in the question, F = 30N, A = 0.06m²

P = F/A

P = 30/0.06

P = 500N/m²

7 0

3 years ago

32 gm of O2 to mole of O2

lana [24]

Molar mass of O2:-

$\\ \rm\longmapsto 2(16u)=32g/mol$

Now

$\boxed{\sf No\:of\;moles=\dfrac{Given\:Mass}{Molar\:Mass}}$

$\\ \rm\longmapsto No\:of\;moles=\dfrac{32}{32}$

$\\ \rm\longmapsto No\:of\;moles=1mol$

5 0

3 years ago

Acetylene is hyrodgenated to form ethane. The feed to the reactor contains 1.60 mol H2/mol C2H2. The reaction proceeds to comple

Black_prince [1.1K]

Answer:

Explanation:

C₂H₂ + 2H₂ = C₂H₆

1 mole 2 mole 1 mole

Feed of reactant is 1.6 mole H₂ / mole C₂H₂

or 1.6 mole of H₂ for 1 mole of C₂H₂

required ratio as per chemical reaction written above

2 mole of H₂ for 1 mole of C₂H₂

So H₂ is in short supply . Hence it is limiting reagent .

1.6 mole of H₂ will react with half of 1.6 mole or .8 mole of C₂H₂ to form .8 mole of C₂H₆

a )Calculate the stoichiometric reactant ratio = mole H₂ reacted/mole C₂H₂ reacted

= 1.6 / .8 = 2 .

b )

yield ratio = mole C₂H₆ formed / mole H₂ reacted ) = 0.8 / 1.6 = 1/2 = 0.5 .

4 0

3 years ago

The half life for the decay of carbon-14 is 5.73 x 10 years. Suppose the activity due to the radioactive decay of the carbon-14

Elena-2011 [213]

Answer:

Age of the atifact is $4.2\times 10^{2}$ years

Explanation:

For first -order radioactive decay- $A_{t}=A_{0}(\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}}$
$A_{t}$ represents activity of radioactive nuclide after t time, $A_{0}$ represents initial activity of radioactive nuclide and $t_{\frac{1}{2}}$ represents half-life
Here, $A_{t}=19Bq$ , $A_{0}=20Bq$ and $t_{\frac{1}{2}}=5.73\times 10^{3}years$