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grandymaker [24]
4 years ago
13

On a coordinate plane, 2 polygons are shown. Polygon A B C D has points (negative 3, 3), (5, 3), (5, negative 1), and (1, negati

ve 5). Polygon A prime B prime C prime D prime has points (negative 5, negative 2), (negative 3, negative 2), (negative 3, negative 3), and (negative 4, negative 4).
Which composition of similarity transformations maps polygon ABCD to polygon A'B'C'D'?

a dilation with a scale factor of One-fourth and then a rotation
a dilation with a scale factor of One-fourth and then a translation
a dilation with a scale factor of 4 and then a rotation
a dilation with a scale factor of 4 and t

Mathematics
2 answers:
ad-work [718]4 years ago
5 0

Answer:

A dilation with a scale factor of One-fourth and then a translation

Step-by-step explanation:

Plot points A, B, C, D, A', B, C' and D' on the coordinate plane and draw quadrilaterals ABCD and A'B'C'D'.

These quadrilaterals are similar and quadrilateral a'B'C'D' has sides 4 times smaller than quadrilateral ABCD.

This means that the dilation with a scale factor of one-fourth was performed.

The figures were not rotated (they have the same positions), so the second transformation was translation.

Hence, correct option is B: a dilation with a scale factor of One-fourth and then a translation

ioda4 years ago
5 0

Answer:

a dilation with a scale factor less than 1 and then a translation

That is the the correct answer

Step-by-step explanation:

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Luis has a change jar that contains only pennies and dimes. he has 74 coins which add up to a total of $4.61. how many of each t
Ghella [55]

p +d = 74 coins

 rewrite as p =74-d

0.01p + 0.10d = 4.61

0.01(74-d) +0.10d = 4.61

0.74 - 0.01d +0.10d =4.61

0.74 +0.09d =4.61

0.09d = 3.87

d = 3.87/.09 = 43

p = 74-43 = 31

 43 dimes and 31 pennies

7 0
4 years ago
^!!Howdy howdy!!^
serious [3.7K]

Answer:

1. >; 2. >  

Step-by-step explanation:

1.

     ⅜ (?) 0.295    Convert ⅜ to a decimal fraction

0.375 (?) 0.295

We can use a <em>number line</em> to decide which number is greater.

In Fig. 1 below, when we go from 0.295 to 0.375, we are moving to the <em>RIGHT</em>,  so 0.375 is greater than 0.295.

0.375 >  0.295

2.

-0.770 (?) -4/5    Convert ⅘ to a decimal fraction

-0.770 (?) -0.800

In Fig. 2 below, when we go from -0.80 to -0.77, we are moving to the <em>RIGHT</em>,  so -0.770 is greater than -0.800.

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3 0
4 years ago
Quadrilateral BCDE is inscribed inside a circle as shown below. Write a proof showing that angles C and E are supplementary.
erma4kov [3.2K]

Each of those angles are Inscribed angles. A useful fact is that the measure of the intercepted arc of an inscribed angle is twice the measure of the angle.

The intercepted arc of ∠C is arc BED. The intercepted arc of ∠E is arc BCD.

m(arc BED) + m(arc BCD) = 2( m∠C + m∠E)

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360 = 2(m∠C + m∠E)
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The angles are supplementary.

4 0
3 years ago
I need help with this proof.<br>​
mylen [45]

Answer:

My proof is in the explanation.  

Step-by-step explanation:

This is a two-column proof.

One column for statements and the other for the reason for that statement.

Hopefully it shows up well on your screen. Let me know if it doesn't.

Statement                                          |        Reason

1) CD is the perpendicular                   1) Given

bisector of AB

2) AD=DB                                              2) Definition of bisector

3) CD=CD                                              3) Reflexive property

4) mAngleCDA=90                               4) Definition of perpendicular

5) mAngleCDB=90                               5) Definition of perpendicular

6) mAngleCDA=mAngleCDB               6) Substitution property

7) Corresponding parts of each           7)  SAS

triangle are congruent                                (side-angle-side)

8) AC=CB                                               8) The two triangles are ............................................................................congruent so

                                                                   the corresponding parts ............................................................................are

                                                                   congruent.

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3 years ago
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mixas84 [53]
Try this:
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