p +d = 74 coins
rewrite as p =74-d
0.01p + 0.10d = 4.61
0.01(74-d) +0.10d = 4.61
0.74 - 0.01d +0.10d =4.61
0.74 +0.09d =4.61
0.09d = 3.87
d = 3.87/.09 = 43
p = 74-43 = 31
43 dimes and 31 pennies
Answer:
1. >; 2. >
Step-by-step explanation:
1.
⅜ (?) 0.295 Convert ⅜ to a decimal fraction
0.375 (?) 0.295
We can use a <em>number line</em> to decide which number is greater.
In Fig. 1 below, when we go from 0.295 to 0.375, we are moving to the <em>RIGHT</em>, so 0.375 is greater than 0.295.
0.375 > 0.295
2.
-0.770 (?) -4/5 Convert ⅘ to a decimal fraction
-0.770 (?) -0.800
In Fig. 2 below, when we go from -0.80 to -0.77, we are moving to the <em>RIGHT</em>, so -0.770 is greater than -0.800.
-0.770 > -0.800
Each of those angles are Inscribed angles. A useful fact is that the measure of the intercepted arc of an inscribed angle is twice the measure of the angle.
The intercepted arc of ∠C is arc BED. The intercepted arc of ∠E is arc BCD.
m(arc BED) + m(arc BCD) = 2( m∠C + m∠E)
The two arcs combined make u p the entire circle, so the sum of their measures is 360.
360 = 2(m∠C + m∠E)
180 = m∠C + m∠E
The angles are supplementary.
Answer:
My proof is in the explanation.
Step-by-step explanation:
This is a two-column proof.
One column for statements and the other for the reason for that statement.
Hopefully it shows up well on your screen. Let me know if it doesn't.
Statement | Reason
1) CD is the perpendicular 1) Given
bisector of AB
2) AD=DB 2) Definition of bisector
3) CD=CD 3) Reflexive property
4) mAngleCDA=90 4) Definition of perpendicular
5) mAngleCDB=90 5) Definition of perpendicular
6) mAngleCDA=mAngleCDB 6) Substitution property
7) Corresponding parts of each 7) SAS
triangle are congruent (side-angle-side)
8) AC=CB 8) The two triangles are ............................................................................congruent so
the corresponding parts ............................................................................are
congruent.
Try this:
Jonny has 50 apples. He has 5 bags. How many apple does Jonny puts in each abg?