Explanation:
Once blood glucose levels increase, pancreatic insulin migrates into a fat cell via the blood stream. Insulin then binds in the plasma membrane of the cell to an Insulin Receptor (IR). Through autophosphorylation, phosphate groups are then added to the IR, causing GLUT4 molecules to come to the cell's surface.
<span>The answer is 2.519 × 10^4. Use the distributive property: a × x + b × x = (a + b) × x. If a = 4.659, b = 2.14, and x = 10^4, then 4.659 × 10^4 − 2.14 × 10^4 = (4.659 - 2.14) × 10^4. Now, subtract numbers in parenthesis: 4.659 × 10^4 − 2.14 × 10^4 = (4.659 - 2.14) × 10^4 = 2.519 × 10^4.Hope this helps. Let me know if you need additional help!</span>
<h2>Answer : The order of conductivity from most conductive to least is this - </h2><h2>Calcium bromide
, Potsassium bromide (KBr), Benzoic acid
and last is sugar.</h2><h3>Explanation : </h3>
When dissolved in water produces three ions namely; 
and 
which acts as best conductor amongst the given choices.
Next is potassium bromide when dissolved in water generates only two ions which are 
and 
and acts as an conductor.
Benzoic acid 
, is a weak acid and is slightly ionized so it acts as an weak conductor.
Sugar is a non ionized compound so it is anon conductor.
A buffer is usually composed of either:
- a weak base combined with its conjugate acid, or
- a weak acid combined with its conjugate base
Now, examining each of the choices:
1- KOH and NH3: since they are both bases, thus this mixture is not a buffer
2- HBr and NaCl: since HBr is a strong acid while NaCl is the salt of another different acid, thus this mixture is not a buffer
3- HCl and HBr: these are both considered to be strong acid, thus this mixture is not a buffer
4- HCHO2 and NaCHO2: as for HCH02, it is considered a weak base while NaCHO2 is considered its conjugate base, thus this mixture is a buffer
Answer: 30
Explanation:
Sulfur S 1
Oxygen O 4
Nitrogen N 2
Hydrogen H 8
15 in total. For 2 moles, 15*2 = 30
