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3 years ago

What would be the resulting charge of carbon (C) after this element loses four electrons?

Physics

1 answer:

Sladkaya [172]3 years ago

7 0

Answer:

Carbon will become positively charged.

The charge of Carbon will be +4.

Explanation:

The charge of Carbon will be +4.

In the periodic table, elements that give out or lose electrons during electrochemical combinations are called electropositive elements. If carbon loses electrons during the chemical combination, Carbon will become positively charged, with a valency equal to the number of electrons that it lost.

This will make carbon have a charge of +4

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What is the wavelength of this wave

zhannawk [14.2K]

$\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}$

Actually Welcome to the Concept of the Waves.

Wavelength is the distance between two consecutive crest or trough.

hence, here the distance is 10cm

So the wavelength is 10cm

===> 10 cm

7 0

3 years ago

Reggie accidentally left his books on top of his car before he left for class. The books stayed on top of his car while he was d

Volgvan

Answer: When Reggie's car turned eastward, his books continued moving northward, causing them to slide off the top of his car. :)

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3 years ago

The current through inductance L is given by I=I0e−t/τ

ohaa [14]

ΔVl = L di/dt
i = i₀e -t/T
di/dt = i₀ × (-1/T) e -t/T
ΔVl = L× (-I/T i₀e -t/T
ΔVl = -L/T i₀e -t/T

b. 15mm, i₀ = 36mA, T = 1.1m
t= Os
ΔVl = 0,491V
C. t = 1ms
ΔVl = 0.198V
t = 2ms
ΔVl = 0.08V

E. t = ms
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4 years ago

Phosphorus (P) is an element with an atomic number of 15 and an atomic mass of 31. How many neutrons are in an atom of phosphoru

BaLLatris [955]

(31-15 = 16).

Explanation:

the element phosphorus (P) has an atomic number of 15 and a mass number of 31. Therefore, an atom of phosphorus has 15 protons, 15 electrons, and 16 neutrons

5 0

3 years ago

Ammonia enters the compressor of an industrial refrigeration plant at 2 bar, −10°C with a mass flow rate of 15 kg/min and is com

Juli2301 [7.4K]

Answer:

a) W=85.225 kW

b) $0.02\frac{kW}{K}$

Explanation:

First, consider the energy balance for the compressor: The energy that enters to the system (W and enthalpy of the feed flow) is equal to the energy that goes out from it (Heat Q and enthalpy of the exit flow):

$W+m*h_1=Q+m*h_2\\W=Q+m*(h_2-h_1)$

Consider the enthalpy data from van Wylen 6th edition, Table B.2.2. According to that, $h_1=h(200kPa,-10C)=1440.6\frac{kJ}{kgK}$ , $h_2=h(1200kPa,140C)=1757.5\frac{kJ}{kgK}$

So, the power input to the compressor is:

$W=6kW+15\frac{kg}{min}*\frac{min}{60s}*(1757.5-1440.6)\frac{kJ}{kg}\\W=85.225kW$

b) The differential entropy change dS for a reversible heat transfer dQ at a temperature T is:

$dS=\frac{dQ}{T}$

This equation can be integrated if the heat transfer surface temperature remains constant, which is the case, giving as a result:

$S_2-S_1=\frac{Q}{T}=\frac{6kW}{300K}=0.02\frac{kW}{K}$

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3 years ago