All categories

3 years ago

If you want to know how energy will move between two objects, what do you

Physics

1 answer:

LenaWriter [7]3 years ago

8 0

Answer:

I believe it is C. Their Temps.

Explanation:

Hope my answer has helped you!

You might be interested in

From 0 seconds to 4 seconds is the acceleration positive or negative?

Alenkinab [10]

Answer:

From 0 -4 seconds the acceleration is positive. (The graph is going upwards.)

From 6-10 seconds the acceleration is negative. (The graph is going downwards.)

7 0

3 years ago

Oceans have a major effect on global climate because water in the oceans holds a large amount of heat. How does the heat absorpt

Goshia [24]

The ocean doesn't just store solar radiation; it also helps to distribute heat around the globe. When water molecules are heated, they exchange freely with the air in a process called evaporation. Ocean water is constantly evaporating, increasing the temperature and humidity of the surrounding air to form rain and storms that are then carried by trade winds, often vast distances. In fact, almost all rain that falls on land starts off in the ocean. The tropics are particularly rainy because heat absorption, and thus ocean evaporation, is highest in this area.

i hope this if not sorry

3 0

3 years ago

Please help fast!! I need this in less than 17 hours!

djyliett [7]

SOLUTION is given in attachment below.

7 0

3 years ago

A car and a train move together along straight, parallel paths with the same constant cruising speed v(initial). At t=0 the car

kogti [31]

Answer:

$t_1 = \frac{v_i}{a_i}$

$t_2 = \frac{v_i}{a_i}$

Δd = $v_it_1 = v_i^2/a_i$

Explanation:

As $v(t) = v_i + at$ , when the car is making full stop, $v(t_1) = 0$ . $a = -a_i$ . Therefore,

$0 = v_i - a_it_1\\v_i = a_it_1\\t_1 = \frac{v_i}{a_i}$

Apply the same formula above, with $v(t_2) = v_i$ and $a = a_i$ , and the car is starting from 0 speed, we have

$v_i = 0 + a_it_2\\t_2 = \frac{v_i}{a_i}$

As $s(t) = vt + \frac{at^2}{2}$ . After $t = t_1 + t_2$ , the car would have traveled a distance of

$s(t) = s(t_1) + s(t_2)\\s(t_1) = (v_it_1 - \frac{a_it_1^2}{2})\\ s(t_2) = \frac{a_it_2^2}{2}$

Hence $s(t) = (v_it_1 - \frac{a_it_1^2}{2}) + \frac{a_it_2^2}{2}$

As $t_1 = t_2$ we can simplify $s(t) = v_it_1$

After t time, the train would have traveled a distance of $s(t) = v_i(t_1 + t_2) = 2v_it_1$

Therefore, Δd would be $2v_it_1 - v_it_1 = v_it_1 = v_i^2/a_i$

8 0

3 years ago

An airplane flying parallel to the ground undergoes two consecutive displacements. The first is 76 km at 39.8◦ west of north, an

sweet [91]

Answer:

162 km

Explanation:

A diagram can be helpful.

Using the law of cosines, we can find the magnitude of the distance (c) to satisfy ...

c^2 = a^2 +b^2 -2ab·cos(C)

where C is the internal angle of the triangle of vectors and resultant. Its value is ...

180° -39.8° -59.9° = 80.3°

Filling in a=76 and b=156, we get ...

c^2 = 76^2 +156^2 -2·76·156·cos(80.3°) ≈ 26116.78

c ≈ √26116.78 ≈ 161.607

The magnitude of the total displacement is about 162 km.

_____

Please note that in the attached diagram North is to the right and East is up. That alteration of directions does not change the angles or the magnitude of the result.

4 0

4 years ago

Read 2 more answers