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Leya [2.2K]
3 years ago
13

We call the elements in the blocks of periods 4-7 and groups 3-12 the

Chemistry
1 answer:
d1i1m1o1n [39]3 years ago
7 0
The elements in the blocks of period 4-7 and group 3-12 in the periodic table are in the d-block and d-block elements  are known as transition metals or transition elements.
Arsenic is a metalloid and it has four electron shells and five valence electrons.
the s and p orbital of Arsenic have 2 and 3 electrons respectively and which makes five valence electrons.



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What property of water enables ice wedging to break rock?
seropon [69]

Answer:

c

Explanation:

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6 0
3 years ago
Flourine is found to undergo 10% radioactivity decay in 366 minutes determine its halflife​
yuradex [85]

Answer:

\boxed{\text{2408 min}}

Explanation:

The integrated rate law for radioactive decay is

\ln\dfrac{N_{0}}{N_{t}} = kt

1. Calculate the decay constant

\begin{array}{rcl}\ln \dfrac{100}{90} & = & k \times 366\\\\1.054 & = & 366k\\\\k & = & \dfrac{1.054 }{366}\\\\k & = & 2.879 \times 10^{-4} \text{ min}^{-1}\\\end{array}\\\\

2. Calculate the half-life

t_{\frac{1}{2}} = \dfrac{\ln2}{k}\\\\t_{\frac{1}{2}} = \dfrac{\ln2}{2.879 \times 10^{-4} \text{ min}^{-1}} = \text{2408 min}\\\\\text{The half-life for decay is } \boxed{\textbf{2408 min}}

8 0
3 years ago
Suppose that 0.410 mol of methane, CH4(g), is reacted with 0.560 mol of fluorine, F2(g), forming CF4(g) and HF(g) as sole produc
Ber [7]

Answer:

The balanced equation for this reaction will be

                            CH4 + 4F2    →  CF4 + 4HF

We can see that 1 mole of methane requires 4 moles of fluorine but we have 0.41 moles of CH4 and 0.56mole of F2

So using the unitary method we will get that

  • 1 mole of CH4 → 4 mole of 4 mole of fluorine
  • 0.41 mole of methane  →  4*0.41 = 1.64 mole of fluorine for complete reaction

but we have only 0.56 mole of fluorine that means fluorine is the limiting reagent and the product will only be formed by only this amount of fluorine.

  • 4 moles of  fluorine →  1 mole of CF4
  • 0.56 mole →  \frac{1}{4} * 0.56 = 0.14mole of CF4
  • 4 moles of fluorine →  4 moles of HF
  • 0.56 mole of fluorine →  0.56 mole of HF

now to find the heat released we have the formula as

DELTA H = n * Delta H of product - n *delta H of reactant

where n is the moles of the reactant and product.

note: since no information is given about the enthalpies of the species we leave it on general equation also you need to add the product side enthalpy of the species present and similarly on the product side.

8 0
3 years ago
How many H atoms in 12H2O?
Ilya [14]

Answer:

24 atoms of H  or 1.4 x 10²⁵ hydrogen atoms

Explanation:

simple method

1 H₂O has  atoms of hydrogen and 1 atom of oxygen

while 12H₂O will have 24 atoms of hydrogen and 12 atom of oxygen

by Avagadros number

molar mass of water H₂0=18.01528 g/mol

1 mole of H₂0 have 2 moles of Hydrogen  

one mole of water= 6.02⋅10²³water molecules =1.2 x 10²⁴hydrogen atoms

12 mole of H₂O   =    1.2 x 10²⁴ x 12=  1.4 x 10²⁵ hydrogen atoms  

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1.4 x 10²⁵ hydrogen atoms   in 12 moles of H₂O

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3 0
3 years ago
Can someone please help me with 363?
Hitman42 [59]

htdtshhthtdhthshAnswer:

yyrgtyht5gggggggggggggggggdggdd

Explanation:

6 0
3 years ago
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