Can someone help me?!!

Physics

1 answer:

Fantom [35]3 years ago

5 0

<h2>Hello!</h2>

The answer is:

The first option, the force tending to lift Rover is equal to 14.5 N.

To calculate the force that is tending to lift Rover vertically, we need to calculate the vertical component force.

Since we know that the angle between the force and the ground is 29°, we can calculate the vertical component of the force using the following formula:

$F_y=Force*Sin(29\°)$

We are given that the force is equal to 30.0 N, so, calculating we have:

$F_y=Force*Sin(29\°)$

$F_y=30N*Sin(29\°)=14.5N$

Also, we can calculate the horizontal component of the force using the following formula:

$F_x=Force*Cos(29\°)$

$F_x=30N*Cos(29\°)=26.24N$

Hence, we have that the correct option is the first option, the force tending to lift Rover is equal to 14.5 N.

Have a nice day!

You might be interested in

An oscilloscope shows a steady sinusoidal signal of 5 Volt peak to peak, which spans 5 cm in vertical direction on the screen. B

Troyanec [42]

Answer:

it will show a continuous rise in value. The rise will be sinusoidal.

Explanation:

3 0

3 years ago

A new roller coaster contains a loop-the-loop in which the car and rider are completely upside down. If the radius of the loop i

levacccp [35]

Answer:

The minimum speed must the car must be 13.13 m/s.

Explanation:

The radius of the loop is 17.6 m. We need to find the minimum speed must the car traverse the loop so that the rider does not fall out while upside down at the top.

We know that, mg be the weight of car and rider, which is equal to the centripetal force.

$mg = \dfrac{mv^2}{r}\\v = \sqrt{rg}\\v = \sqrt{17.6\times 9.8}\\v = 13.13\ m/s\\$