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3241004551 [841]
3 years ago
8

Can someone help me?!!

Physics
1 answer:
Fantom [35]3 years ago
5 0
<h2>Hello!</h2>

The answer is:

The first option, the force tending to lift Rover is equal to 14.5 N.

<h2>Why?</h2>

To calculate the force that is tending to lift Rover vertically, we need to calculate the vertical component force.

Since we know that the angle between the force and the ground is 29°, we can calculate the vertical component of the force using the following formula:

F_y=Force*Sin(29\°)

We are given that the force is equal to 30.0 N, so, calculating we have:

F_y=Force*Sin(29\°)

F_y=30N*Sin(29\°)=14.5N

Also, we can calculate the horizontal component of the force using the following formula:

F_x=Force*Cos(29\°)

F_x=30N*Cos(29\°)=26.24N

Hence, we have that the correct option is the first option, the force tending to lift Rover is equal to 14.5 N.

Have a nice day!

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Explanation:

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If a 0.750M solution exerts an osmotic pressure of 22.5atm, what must be the temperature (in Kelvin) of the solution
faust18 [17]

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T = 365.58 K

Explanation:

Given that,

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The formula for the osmotic pressure is given by :

P=CRT

Where

R is gas constant, R=0.08206\ L\ atm/mol-K

T=\dfrac{P}{CR}\\\\=\dfrac{22.5}{0.75\times 0.08206}\\\\=365.58\ K

So, the temperature of the solution is 365.58 K.

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An empty 230 kg elevator accelerates upward
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Water has a mass per mole of 18.0 g/mol, and each water mo- lecule (H2O) has 10 electrons. (a) How many electrons are there in o
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Answer:

Part 1) Number of electrons in 1 liter of water equalsN=3.346\times 10^{26}

Part 2) Net charge of all the electrons equals Charge=53.61\times 10^{6}

Explanation:

Since we know that the density of water is 1 kilogram per liter thus we infer that mass of 1 liter of water is 1 kilogram hence we need to find electron's in 1 kg of water.

Now since it is given that molar mass of water is 18.0 grams this means that 1 mole of water contains 18 grams of water.

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Now since it is given that each molecule has 10 electron's thus the total number of electrons in n' molecules equals

N=10\times 3.346\times 10^{25}\\\\N=3.346\times 10^{26}

Part 2)

We know that charge of 1 electron equals 1.602\times 10^{-19}C the the charge of electrons in 'N' quantity equals

Charge=1.6022\times 10^{-19}\times 3.346\times 10^{26}\\\\Charge=52.61\times 10^{6}Columbs  

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