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3241004551 [841]
3 years ago
8

Can someone help me?!!

Physics
1 answer:
Fantom [35]3 years ago
5 0
<h2>Hello!</h2>

The answer is:

The first option, the force tending to lift Rover is equal to 14.5 N.

<h2>Why?</h2>

To calculate the force that is tending to lift Rover vertically, we need to calculate the vertical component force.

Since we know that the angle between the force and the ground is 29°, we can calculate the vertical component of the force using the following formula:

F_y=Force*Sin(29\°)

We are given that the force is equal to 30.0 N, so, calculating we have:

F_y=Force*Sin(29\°)

F_y=30N*Sin(29\°)=14.5N

Also, we can calculate the horizontal component of the force using the following formula:

F_x=Force*Cos(29\°)

F_x=30N*Cos(29\°)=26.24N

Hence, we have that the correct option is the first option, the force tending to lift Rover is equal to 14.5 N.

Have a nice day!

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Answer:

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Explanation:

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A free flow body diagram illustrating what the question represents is attached in the file below;

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Considering the forces on the horizontal axis:

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which can be written also as:

\mu_s N_A + \mu_s N_B  = P

\mu_s( N_A +  N_B)  = P

replacing our value from equation (1)

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b) Since the horizontal distance between the casters A and B is 480 mm; Then half the distance = 480 mm/2 = 240 mm = 0.24 cm

the largest value of "h" allowed for  the cabinet is not to tip over is calculated by determining the limiting condition  of the unbalanced torque whose effect is canceled by the normal reaction at N_A and it is shifted to N_B:  

Then:

\sum M _B = 0

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h =\frac{45*9.8*0.24}{132.3}

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